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astra-53 [7]
2 years ago
14

What is the surface area? 5 in 4 in 5 in 10 in 6 in

Mathematics
1 answer:
fredd [130]2 years ago
7 0
I think the answer is 10
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I REALLY NEED HELP!!! If someone can answer this quickly and correctly I will give them Brainliest. 1. What is the function rule
Rainbow [258]

Answer:

y= -4x + 3

Step-by-step explanation:

Because the slope is -4/1 which is the same as 4 and 3 is the y-intercept.

Here's the work;

We can just use the first two coordinates which are (0,3) and (1,-1) to get from the x-value 0 to 1 we add 1. and to get from the y-value 3 to -1 we subtract 4. Therefore the slope is -4 and the y- intercept (when x is zero) is 3. Pop that into slope intercept form to get y=-4x +3

Hope that helps and have a great day!

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2 years ago
Find the slope of the line that passes through (8, 4) and (2, 9).
Alekssandra [29.7K]
The answers is not -5/6
5 0
3 years ago
A plant has a height of 8 1/4 inches what is the height of the plant after it grows 1 7/8 inches?
laila [671]

Answer:

18

Step-by-step explanation:

3 0
2 years ago
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Write an equation in slope-intercept form for a line with m = 3 and includes the<br> point (0, 2).
maxonik [38]

Answer:

y=3x+2

Step-by-step explanation:

dont put  0 because it dont make sense

if you put 0 n the equation, you will not will get the right equation

7 0
3 years ago
. Find the area of the regular dodecagon inscribed in a circle if one vertex is at (3, 0).
devlian [24]

Answer:

Area of the regular dodecagon inscribed in a circle will be 27 square units.

Step-by-step explanation:

A regular dodecagon is the structure has twelve sides and 12 isosceles triangles inscribed in a circle as shown in the figure attached.

Since angle formed at the center by a polygon = \frac{360}{n}

Therefore, angle at the center of a dodecagon = \frac{360}{12} = 30°

Since one of it's vertex is (3, 0) therefore, one side of the triangle formed or radius of the circle = 3 units

Now area of a small triangle = \frac{1}{2}.(a).(b).sin\theta

where a and b are the sides of the triangle and θ is the angle between them.

Now area of the small triangle = \frac{1}{2}.(3).(3).sin30

= \frac{9}{4}

Area of dodecagon = 12×area of the small triangle

= 12×\frac{9}{4}

= 27 unit²

Therefore, area of the regular octagon is 27 square unit.

4 0
2 years ago
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