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3 years ago

If a system of equations has a solution What would the GraphAre look-alike

Mathematics

1 answer:

pickupchik [31]3 years ago

3 0

Answer:

their intersection point(s)

Step-by-step explanation:

The Solution to a system of equations is the point at which the lines intersect eachother

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-68C 57C How many degrees separate these two temperatures

mafiozo [28]

Answer:

wait what the letter look weird ?

Step-by-step explanation:

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3 years ago

Read 2 more answers

Which is equivalent to this expression? 2/150 + 3/75

Lesechka [4]

Answer:

Step-by-step explanation:

$\frac{2}{150}$ First reduce this to lowest term

$\frac{2}{150}=\frac{1}{75}\\\\\frac{2}{150}+\frac{3}{75}=\frac{1}{75}+\frac{3}{75}\\\\=\frac{1+3}{75}=\frac{4}{75}\\$

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4 years ago

Find the measure of the numbered angles in rhombus ABCD

sasho [114]

Answer:

see the explanation

Step-by-step explanation:

we know that

In a Rhombus opposite angles are congruent and consecutive angles are supplementary

The diagonals are perpendicular and bisect the angles

step 1

Find the measure of angle 4

we know that

$m\angle 4=27^o$ --->by the diagonals bisect the angles

step 2

Find the measure of angle 1

we know that

$m\angle 1=27^o$ ----> by opposite angles are congruent

step 3

Find the measure of angle 2

we know that

$m\angle 1=m\angle 2$ ----> by the diagonals bisect the angles

$m\angle 2=27^o$

step 4

Find the measure of angle 3

we know that

$m\angle 3=90^o$ ----> by the diagonals are perpendicular

step 5

Find the measure of angle 5

we know that

$m\angle 5+27^o=90^o$ ----> by complementary angles

$m\angle 5=90^o-27^o=63^o$

step 6

Find the measure of angle 6

we know that

$m\angle 6=m\angle 5$ ----> by the diagonals bisect the angles

$m\angle 6=63^o$

3 0

3 years ago

A twelve-sided die with sides labeled through will be rolled once. Each number is equally likely to be rolled. What is the proba

FromTheMoon [43]

Complete Question:

A twelve-sided die with sides labeled 1 through 12 will be rolled once. Each number is equally likely to be rolled, what is the probability of rolling a number greater than 10?

Answer:

$P(T) = \frac{1}{6}$

Step-by-step explanation:

Given

Number of Sides = 12

Required

Probability of obtaining a side greater than 10

We start by listing out the sample space;

$S = \{1,2,3,4,5,6,7,8,9,10,11,12\}$

$n(S) = 12$

Next, we list out digits greater than 10; Represent this with T

$T = \{11,12\}$

$n(T) = 2$

Probability of T is calculated as follows;

$P(T) = \frac{n(T)}{n(S)}$

$P(T) = \frac{2}{12}$

Divide the numerator and denominator by 2

$P(T) = \frac{1}{6}$

Hence, the required probability is  $\frac{1}{6}$ 

8 0

3 years ago

Mimi started a pattern whit 5 and used the rule add 10

guajiro [1.7K]

Answer:

This seems like an incomplete question...

Step-by-step explanation:

The pattern would go 5...15...25...35...45...55... and so on.

Hope this is the answer you were looking for!! :)

3 0

3 years ago