Question

Calculate the gravitational force between a 4.0 x 10^8 kg mass and a 2.8 x 10^5 kg mass separated by a distance of 1.0 x 10^4 m.

Answer 1

Answer:

$F_{g}=7.4704\times10^{-5}$

Explanation:

Givens: d = 1.0 × $10^{4}$  $m_{1} = 4.0 x 10^{8}$  $m_{2} = 2.8$×$10^{5}$

Required: $F_{g}=?$

Formula:  $F_{g}= \frac{(6.67x10^{-11})(m_{1})(m_{2}) }{d^{2}}$    (6.67x10^-11  is the gravitational constant)

$F_{g}=\frac{\left(6.67\cdot10^{-11}\right)\left(4.0\cdot10^{8}\right)\left(2.8\cdot10^{5}\right)}{\left(1.0\cdot10^{4}\right)^{2}}$

$F_{g}=7.4704\times10^{-5}$