Answer:
1) Q ’= 8 Q
, 2) q ’= 16 q
, 3) r ’= ¾ r
Explanation:
For this exercise we will use Coulomb's law
F = k q Q / r²
It asks us to calculate the change of any of the parameters so that the force is always F
Original values
q, Q, r
Scenario 1
q ’= 2q
r ’= 4r
F = k q ’Q’ / r’²
we substitute
F = k 2q Q ’/ (4r)²
F = k 2q Q '/ 16r²
we substitute the value of F
k q Q / r² = k q Q '/ 8r²
Q ’= 8 Q
Scenario 2
Q ’= Q
r ’= 4r
we substitute
F = k q ’Q / 16r²
k q Q / r² = k q’ Q / 16 r²
q ’= 16 q
Scenario 3
q ’= 3/2 q
Q ’= ⅜ Q
we substitute
k q Q r² = k (3/2 q) (⅜ Q) / r’²
r’² = 9/16 r²
r ’= ¾ r
Answer:
White dwarfs because you look at where the highest temperature is and where is the highest magnitude. Fun fact, the sun will become a white dwarf.
Explanation:
As per the question there are two ohmic devices.
The first ohmic device is a good conductor and the second one is a good insulator.
As per Ohm's law the current flowing through a conductor is directly proportional to the potential difference maintained across the two ends of a conductor at constant temperature and pressure. If V is the potential and I is the current flow through these Ohmic devices,then mathematically it can be written as-
V∝ I [ at constant temperature and pressure]
⇒V= IR
Here R is the proportionality constant called resistance of the material.
Hence the resistance R is calculated as -

Now a graph is plotted taking potential V on X-axis and current I along Y- axis.
The graph will be a straight line for conductor and will be a curve depending on the type of insulator.
The slope of this graph will give the resistance of the material.
An insulator is a substance through which current flow is very low as its resistance is very high.Hence the slope of the V-I curve is very large.
A conductor is that substance through which current is flown easily as the resistance of conductor is very low.Hence the slope of V-I curve is smaller,
pulling farther back on the string
Explanation:
pulling back will increase kinetic energy
Answer:
Explanation:
The energy lost by the handle in lowering is equal to the energy gained by the car in raising the height.
As the mass of car is much more as compared to the jack, so the height raised by the car is very small as compared to the handle of jack.