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Morgarella [4.7K]
2 years ago
15

There is a square loop of wire with side length L moving to the right at a speed of v. The resistance in the wire is R. To the r

ight of it is a region with a magnetic field with field strength B into the page. Find the current in the wire loop (a) before the loop reaches the magnetic field, (b) while the loop is entering the field, (c) while the loop is entirely within the field, (d) while the loop is exiting the field, and (e) after the loop leaves the field. Be sure to include the direction of the current (i. s. clockwise or counter-clockwise). All your answers will be in terms of L, v, B, and R.
Physics
1 answer:
topjm [15]2 years ago
8 0

There is a square loop of wire with side length L moving to the right at a speed of v. The resistance in the wire is R. To the right of it is a region with a magnetic field with field strength B into the page.  of anxiety (low vs. high) and stress (low vs. moderate vs. high) on test.

Everyone experiences anxiety occasionally, but persistent anxiety can reduce your quality of life. Though likely best known for altering behavior, worry can have negative effects on our physical health. Anxiety speeds up our heartbeat and breathing, resistance blood flow to the parts of our brains that need it. You are getting ready for a challenging situation by having this extremely bodily reaction. Test performance may be impacted by anxiety. According to studies, pupils with low levels of test anxiety perform better on multiple-choice resistance (MCQ) exams than pupils with high levels of anxiety. Studies have indicated that female students have greater levels of test anxiety than male students.

Learn more about anxiety here:

brainly.com/question/4913240

#SPJ4

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Read 2 more answers
An amoeba has 1.00 x 1016 protons and a net charge of 0.300 pC. Assuming there are 1.88 x 106 fewer electrons than protons, If y
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The fraction of the protons would have no electrons =1.88\times 10^{-10}

Explanation:

We are given that

Amoeba has total number of protons=1.00\times 10^{16}

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Electrons are fewer than protons=1.88\times 10^6

We have to find the fraction of protons would have no electrons.

The fraction of the protons would have no electrons

=\frac{Fewer\;electrons}{Total\;protons}

The fraction of the protons would have no electrons

=\frac{1.88\times 10^{6}}{1.00\times 10^{16}}

=1.88\times 10^{-10}

Hence, the fraction of the protons would have no electrons =1.88\times 10^{-10}

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