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anygoal [31]
3 years ago
6

The average force applied to move an initially stationary golf cart over a period of 25 s is 500 N. What is the change in moment

um of the cart?
Physics
1 answer:
Yuki888 [10]3 years ago
6 0

Answer:

12500(kg*m/s)

Explanation:

F=ma=mv/t=p/t

p=F*t=500N*25 s=12500(kg*m/s)

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A 600W toaster, 1200W iron and a 100W bulb are all connected to household 120V circuit. a) find the current drawn by each applia
Advocard [28]

Answer:

(a) %a, 10 A, 0.833 A

(b) 12 ohm

(c) $22.8

Explanation:

Power of toaster, P1 = 600 W

Power of iron, P2 = 1200 W

Power of bulb, P3 = 100 W

V = 120 V

As they are in household circuit, so they are connected in parallel, so the voltage is same for all.

(a) Use the formula P = V x i

Current in toaster, i1 = P1 / V = 600 / 120 = 5 A

Current in iron, i2 = P2 / V = 1200 / 120 = 10 A

Current in bulb, i3 = P3 / V = 100 / 120 = 0.833 A

(b) Resistance of heating element of iron is R2.

V = i2 x R2

120 = 10 x R2

R2 = 12 ohm

(c) Total energy consumed in 24 hours for 5 days

                              = (600 + 1200 + 100) x 24 x 5 = 228000 Wh = 228 KWh

Cost of 1 KWh = $0.1

Cost of 228 KWh = 0.1 x 228 = $22.8

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3 years ago
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If cats always land on their feet, how do they get hurt when they fall?
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The impact front the fall, depending on the distance, has an effect on the impact of their bones crushing with the pressure from the fall.
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Bryan Allen pedaled a human-powered aircraft across the English channel from the cliffs of Dover to Cap Gris-Nez on June 12, 197
tigry1 [53]

Answer:

The answer is "5.53 \ \frac{m}{s}"

Explanation:

apply the formula for calculating the average velocity to the relative air

V_{PG} =V_{PA}+V_{AG}

\Rightarrow  V_{PA} = V_{PG} -V_{AG}

Given value:

V_{AG} = -2 \ \frac{m}{s}

V_{PG} =3.53

\Rightarrow  V_{PA} = 3.53 - (-2) \\\\\Rightarrow  V_{PA} = 3.53 +2 \\\\\Rightarrow  V_{PA} = 5.53  \\\\

The final answer is "5.53 \ \frac{m}{s}" in the south-east direction.

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7 0
3 years ago
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A rocket accelerates by burning its onboard fuel, so its mass decreases with time. Suppose the initial mass of the rocket at lif
Serggg [28]

Answer:

Height of the rocket be one minute after liftoff is 40.1382 km.

Explanation:

v(t)=-gt-v_e\times \ln \frac{m-rt}{m}

v = velocity of rocket at time t

g = Acceleration due to gravity =9.8 m/s^2

v_e = Constant velocity relative to the rocket = 2,900m/s.

m = Initial mass of the rocket at liftoff = 29000 kg

r = Rate at which fuel is consumed = 170 kg/s

Velocity of the rocket after 1 minute of the liftoff =v

t = 1 minute = 60 seconds'

Substituting all the given values in in the given equation:

v(60)=-9.8 m/s^2\times 60 s-2,900m/s\times \ln (\frac{29,000 kg-170 kg/s\times 60 s}{2,9000 kg})

v(60) = 668.97 m/s

Height of the rocket = h

Velocity=\frac{Displacement}{time}

668.97 m/s=\frac{h}{60 s}

h=668.97 m/s\times 60 s=40,138.2 m = 40.1382 km

Height of the rocket be one minute after liftoff is 40.1382 km.

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3 years ago
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