2π is the period of `y = 1+ tan((1)/(2)x)`
The limit does not exist. Why? Because the left hand limit DOES NOT equal the right hand limit. Let’s double check:
We could use -0.000001 to represent the left hand limit. This is less than 0. We plug in 5x - 8
5(-0.000001) - 8
-0.000005 - 8
-8.000005
If we would continue the limit (extend the zeros to infinity), we would get exactly
-8
That is our left hand limit.
Our right hand limit will be represented by 0.000001. This is greater than 0. We plug in abs(-4 - x)
abs(-4 - (0.000001))
abs(-4.000001)
4.000001
If we would continue the limit (extend the zeros to infinity), we would get exactly
4
4 does not equal -8, therefore
The limit does not exist
Answer:
A and D
Step-by-step explanation:
Answer:
5.7
Step-by-step explanation:
<u>unrelated</u>, I love how peter is open about buying makeup. i feel as if the gender roles are garbage. #YasQueen #GoPeter #PeterIsCool #MakeupCanBeForBoysToo <3
(also peter could totally be a girl and I am misgendered a person)
Answer:
t = 74 / 9
Step-by-step explanation:
-9(t - 2) = 4(1 - 15)
-9t + 18 = 4 - 60
-9t + 18 = -56
-18 -18
-9t = -74
/-9 /-9
t = 74 / 9
t = 8.22
