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3 years ago

Two fair, six-sided dice are rolled. What is the probability that the resulting total is even or greater than 10?

Mathematics

2 answers:

zalisa [80]3 years ago

7 0

Answer:

The probability would be 6/ 36

Step-by-step explanation:

Sonja [21]3 years ago

5 0

Answer:

Step-by-step explanation:

Since there are a total of 6 x 6 = 36 outcomes, then the probability that the sum will be greater than 10 is 3/36 = 1/12.

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Step-by-step explanation:

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3 years ago

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3 years ago

Read 2 more answers

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konstantin123 [22]

Answer:

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3 years ago

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3 years ago

student randomly receive 1 of 4 versions(A, B, C, D) of a math test. What is the probability that at least 3 of the 5 student te

alexdok [17]

Answer:

1.2%

Step-by-step explanation:

We are given that the students receive different versions of the math namely A, B, C and D.

So, the probability that a student receives version A = $\frac{1}{4}$ .

Thus, the probability that the student does not receive version A = $1-\frac{1}{4}$ = $\frac{3}{4}$ .

So, the possibilities that at-least 3 out of 5 students receive version A are,

1) 3 receives version A and 2 does not receive version A

2) 4 receives version A and 1 does not receive version A

3) All 5 students receive version A

Then the probability that at-least 3 out of 5 students receive version A is given by,

$\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{3}{4}\times \frac{3}{4}$ + $\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{3}{4}$ + $\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}$