2 years ago

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Mathematics

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sergij07 [2.7K]2 years ago

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Given that f(x) = x2 + 2x + 3 and g(x) = quantity of x plus four, over three , solve for f(g(x)) when x = 2.

Sidana [21]

$f(x)=x^2+2x+3$
$g(x)=\frac{x+4}{3}$
$f(g(x))=(\frac{x+4}{3})^2+2(\frac{x+4}{3})+3$
$f(g(x))=\frac{x^2+8x+16}{9}+\frac{2x+8}{3}+3$
$f(g(2))=\frac{2^2+8(2)+16}{9}+\frac{2(2)+8}{3}+3$
$f(g(2))+\frac{4+16+16}{9}+\frac{4+8}{3}+3$
$f(g(2))=\frac{36}{9}+\frac{12}{3}+3$
$f(g(2))=4+4+3$
$f(g(2)=11$

Check:
g(2)=(2+4)/3=2
f(2)=2^2+2(2)+3=4+4+3=11 Checks.

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3 years ago

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Solve for x <br> X= 6<br> X=15<br> X=30<br> X=90

Natalija [7]

Answer:

x=30

Step-by-step explanation:

4x+2x=180

6x=180

x=30

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