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4 years ago

I need help desperately a,b and c

Mathematics

1 answer:

Degger [83]4 years ago

5 0

A. Addition property. B. Distributive property c. The multiplication property. Hope that helps

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Anyone know the answers 11 through 20?

Evgen [1.6K]

Step-by-step explanation:

11) x^5

12) 5x^2

13) x+21

14) 2x-8

15) 3^3

=3*3*3

=27

16)2^5

=2*2*2*2*2

=32

17) 5^4

=5*5*5*5

=625

18)2 times a number p squared

19)3 times a number m fifth power

20)the addition of half a number and 2

5 0

3 years ago

There are 29235 marbles and 371 jacks. If you want to know the percentage of jacks, do you divide the first number by the second

garik1379 [7]

Answer:

Correct answer: Two decimal places to the right

Step-by-step explanation:

We will set the classic proportion:

29,235 - 100%

371 - x%

29,235 : 371 = 100 : x ⇒ 29,235 · x = 371 · 100

x = (371/ 29,235) · 100 = 0.0127 · 100 = 1.27%

x = 1.27%

You divide first number by the second and then multiply with 100,

which is the same as moving the decimal point two places to the right.

God is with you!!!

3 0

3 years ago

Can someone help??.?.

Butoxors [25]

Answer: 8/100

Step-by-step explanation: I converted 5/10 in 50/100 and subtracted 50 from 58 and got 8 so the answer is 8/100.

8 0

3 years ago

Read 2 more answers

Find the perimeter of WXYZ. Round to the nearest tenth if necessary.

yanalaym [24]

Answer:

C. 15.6

Step-by-step explanation:

Perimeter of WXYZ = WX + XY + YZ + ZW

Use the distance formula, $d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$ to calculate the length of each segment.

✔️Distance between W(-1, 1) and X(1, 2):

Let,

$W(-1, 1) = (x_1, y_1)$

$X(1, 2) = (x_2, y_2)$

Plug in the values

$WX = \sqrt{(1 - (-1))^2 + (2 - 1)^2}$

$WX = \sqrt{(2)^2 + (1)^2}$

$WX = \sqrt{4 + 1}$

$WX = \sqrt{5}$

$WX = 2.24$

✔️Distance between X(1, 2) and Y(2, -4)

Let,

$X(1, 2) = (x_1, y_1)$

$Y(2, -4) = (x_2, y_2)$

Plug in the values

$XY = \sqrt{(2 - 1)^2 + (-4 - 2)^2}$

$XY = \sqrt{(1)^2 + (-6)^2}$

$XY = \sqrt{1 + 36}$

$XY = \sqrt{37}$

$XY = 6.08$

✔️Distance between Y(2, -4) and Z(-2, -1)

Let,

$Y(2, -4) = (x_1, y_1)$

$Z(-2, -1) = (x_2, y_2)$

Plug in the values

$YZ = \sqrt{(-2 - 2)^2 + (-1 -(-4))^2}$

$YZ = \sqrt{(-4)^2 + (3)^2}$

$YZ = \sqrt{16 + 9}$

$YZ = \sqrt{25}$

$YZ = 5$

✔️Distance between Z(-2, -1) and W(-1, 1)

Let,

$Z(-2, -1) = (x_1, y_1)$

$W(-1, 1) = (x_2, y_2)$

Plug in the values

$ZW = \sqrt{(-1 -(-2))^2 + (1 - (-1))^2}$

$ZW = \sqrt{(1)^2 + (2)^2}$

$ZW = \sqrt{1 + 4}$

$ZW = \sqrt{5}$

$ZW = 2.24$

✅Perimeter = 2.24 + 6.08 + 5 + 2.24 = 15.56

≈ 15.6

5 0

3 years ago

The absolute value of a number is its distance from 0 on a number line. True or False ?

Aleonysh [2.5K]

true.

but the absolute value of 3 is 3 and -3 is 3. 6=6 -6=6

4 0

3 years ago

Read 2 more answers