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zhuklara [117]
2 years ago
9

The sum of 10x + 6 and -x + 8

Mathematics
1 answer:
zubka84 [21]2 years ago
4 0

9x +14

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Please explain your answer
Irina18 [472]
\text{Distance = } \sqrt{(5 + 8)^2+ (-3 + 3)^2 }=   \sqrt{13^2} = 13

Answer: 13 units
6 0
2 years ago
A tunnel is in the shape of a parabola. The maximum height is 31 m and it is 13 m wide at the base as shown below.
yan [13]
Using the given values from the problem and the illustration, three points are known which are (0,0), (6.5,-31), (-6.5,-31). The first step in solving this problem is to determine the equation of the parabola.
y = ax²
-31 = a(6.5)²
-31 = 42.25a 
a = -31/42.25 
a = -124/169 

Therefore, the equation of the parabola is y = (-124/169)x². The value 4.5 is then substituted in the equation as x to get the answer which is 16.14 meters.
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2 years ago
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pshichka [43]
I believe it is the second one hope that helped
4 0
1 year ago
Read 2 more answers
Which statement best describes the polynomial 3x^2-6+4x^4
Elanso [62]
<span>fourth degree polynomial with three terms
the degree is the highest exponent the term are separated by plus or minus  </span>
8 0
3 years ago
Determine and state the coordinates of the center and the length of the radius of the
zmey [24]

we can see that the center is (-3, 3) and the radius is 9 units.

<h3 /><h3>How to find the center and radius of the circle?</h3>

The general circle equation, for a circle with a center (a, b) and radius R is given by:

(x - a)^2 + (y - b)^2 = R^2

Here we have the equation:

x^2 + y^2 + 6x = 6y + 63

Let's complete squares:

x^2 + y^2 + 6x - 6y =  63

(x^2 + 6x) + (y^2 - 6y) = 63

(x^2 + 2*3x) + (y^2 - 2*3y) = 63

Now we can add and subtract 9, (two times) so we get:

(x^2 + 2*3x + 9) - 9 + (x^2 - 2*3x + 9) - 9 = 63

(x + 3)^2 + (y - 3)^2 = 63 + 9 + 9 = 81 = 9^2

(x + 3)^2 + (y - 3)^2 = 9^2

Comparing with the general circle equation, we can see that the center is (-3, 3) and the radius is 9 units.

If you want to learn more about circles:

brainly.com/question/1559324

#SPJ1

7 0
2 years ago
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