All categories

4 years ago

Please help????????????? (ASAP)

Mathematics

1 answer:

Rina8888 [55]4 years ago

8 0

Answer: 12

Step-by-step explanation:

$\frac{b}{3}+16=20$

Subtract 16

$\frac{b}{3}=20-16$

$\frac{b}{3}=4$

Multiply by 3

$b=4*3$

$b=12$

You might be interested in

Help pleasseeeee ! 15 points the answers are (-1,-5) (0,-3) (4,5) (9,15)

svet-max [94.6K]

Answer:

(0,-3)

Step-by-step explanation:

2x-y = 3

x+2y = -6

Multiply the first equation by 2 so we can eliminate y

2(2x-y =3)

4x -2y = 6

Add this to the second equation

4x -2y = 6

x+2y = -6

-----------------

5x +0y = 0

x = 0

Now find t

x+2y = -6

0+2y = -6

2y =-6

Divide by 2

y = -3

5 0

3 years ago

Read 2 more answers

Show work please !!!

aleksklad [387]

Answer:

512x⁴y¹²

Step-by-step explanation:

its a cube so length x width x height

8xy⁴ times 8xy⁴ times 8xy⁴ is 512x³y¹²

5 0

3 years ago

Pls pls help! super desperate. find the lateral surface areas of the shapes shown in the photo

Alja [10]

Answer:

3- 0.14 2- 841

Step-by-step explanation:

3- 0.7*0.2=0.14

2- 56/2= 28

28*28+29*29= 841*841

square root of 841*841= 841

3 0

3 years ago

Kim has a living room that measures 12 feet by 12 feet. She wants to buy the largest circular area rug that she can find for the

galina1969 [7]

Answer: 10 foot radius

Step-by-step explanation:

8 0

3 years ago

A person stands 10 meters east of an intersection and watches a car driving towards the intersection from the north at 13 meters

In-s [12.5K]

Answer:

Therefore the rate change of distance between the car and the person at the instant, the car is 24 m from the intersection is 12 m/s.

Step-by-step explanation:

Given that,

A person stand 10 meters east of an intersection and watches a car driving towards the intersection from the north at 13 m/s.

From Pythagorean Theorem,

(The distance between car and person)²= (The distance of the car from intersection)²+ (The distance of the person from intersection)²+

Assume that the distance of the car from the intersection and from the person be x and y at any time t respectively.

∴y²= x²+10²

$\Rightarrow y=\sqrt{x^2+100}$

Differentiating with respect to t

$\frac{dy}{dt}=\frac{1}{2\sqrt{x^2+100}}. 2x\frac{dx}{dt}$

$\Rightarrow \frac{dy}{dt}=\frac{x}{\sqrt{x^2+100}}. \frac{dx}{dt}$

Since the car driving towards the intersection at 13 m/s.

so, $\frac{dx}{dt}=-13$

$\therefore \frac{dy}{dt}=\frac{x}{\sqrt{x^2+100}}.(-13)$

Now

$\therefore \frac{dy}{dt}|_{x=24}=\frac{24}{\sqrt{24^2+100}}.(-13)$

$=\frac{24\times (-13)}{\sqrt{676}}$

$=\frac{24\times (-13)}{26}$

= -12 m/s

Negative sign denotes the distance between the car and the person decrease.

Therefore the rate change of distance between the car and the person at the instant, the car is 24 m from the intersection is 12 m/s.

8 0

3 years ago