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nignag [31]
3 years ago
5

{7TH GRADE} Create four (4) problems that include fractions. Solve the problems using estimation.

Mathematics
2 answers:
zaharov [31]3 years ago
8 0

Answer:

Step-by-step explanation:

.

bulgar [2K]3 years ago
3 0
1/4 +2/3 =
3/4 - 1/7
6/8 / 9/12
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A researcher believes that the mean weight of competitive runners is about 140 pounds. A sample of 24 elite distance runners has
ExtremeBDS [4]

Answer:

t=\frac{136-140}{\frac{11}{\sqrt{24}}}=-1.781    

p_v =P(t_{(23)}  

If we compare the p value and the significance level assumed \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the mean is less than 140 pounds at 5% of signficance.  

Step-by-step explanation:

Data given and notation  

\bar X=136 represent the sample mean

s=11 represent the sample standard deviation

n=24 sample size  

\mu_o =140 represent the value that we want to test

\alpha=0.01 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is less than 140, the system of hypothesis would be:  

Null hypothesis:\mu \geq 140  

Alternative hypothesis:\mu < 140  

If we analyze the size for the sample is < 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

t=\frac{136-140}{\frac{11}{\sqrt{24}}}=-1.781    

P-value

The first step is calculate the degrees of freedom, on this case:  

df=n-1=24-1=23  

Since is a one left tailed test the p value would be:  

p_v =P(t_{(23)}  

Conclusion  

If we compare the p value and the significance level assumed \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the mean is less than 140 pounds at 5% of signficance.  

4 0
3 years ago
What happens when a zero is added to the far right of a decimal number?
Westkost [7]
Adding a zero on the right changes the place value of all the other digits
3 0
3 years ago
We often deal with weighted​ means, in which different data values carry different weights in the calculation of the mean. For​
Veseljchak [2.6K]

Answer:

a) The student's overall average for the class is 87.97.

b) He would need a score above 100 to get an A, which means that he could not have scored high enough on the final exam to get an A in the class.

Step-by-step explanation:

Weighed average:

To solve this question, we find the student's weighed average, multiplying each of his grade by his weights.

Grades and weights:

Scored 82.5 on the midterm, worth 30%.

Scored 88.6 on the final exam, worth 30%.

Scored 91.6 on the homework, worth 40%.

a. On a 100-point scale, what is the student's overall average for the class?

Multiplying each grade by it's weight:

A = 82.5*0.3 + 88.6*0.3 + 91.6*0.4 = 87.97

The student's overall average for the class is 87.97.

b. The student was hoping to get an A in the class, which requires an overall score of 93.5 or higher. Could he have scored high enough on the final exam to get an A in the class?

Score of x on the final class, and verify that the average could be 93.5 or higher. So

A = 82.5*0.3 + 88.6*0.3 + 0.4x

A \geq 93.5

82.5*0.3 + 88.6*0.3 + 0.4x \geq 93.5

0.4x \geq 93.5 - (82.5*0.3 + 88.6*0.3)

x \geq \frac{93.5 - (82.5*0.3 + 88.6*0.3)}{0.4}

x \geq 105.425

He would need a score above 100 to get an A, which means that he could not have scored high enough on the final exam to get an A in the class.

3 0
3 years ago
Whats 1+1 you get brainiest​
Otrada [13]

Answer:

1+1=2 ........................

3 0
3 years ago
Read 2 more answers
The point slope form of X-3Y=-27
garik1379 [7]
X-3y=-27
-3y=-27-x
y=(1/3)x+(27/3)
I hope I Helped..
7 0
3 years ago
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