Which property of aluminium makes it a suitable metal for soft-drink can?

A gas mixture contains 3.0 mol of hydrogen (H2) and 7.3 mol of nitrogen (N2). The total pressure of the mixture is 304 kPa. What

Inga [223]

Answer:

Mole fraction H₂ = 0.29

Partial pressure of H₂ → 88.5 kPa

Explanation:

You need to know this relation to solve this:

Moles of a gas / Total moles = Partial pressure of the gas / Total pressure

Total moles = 3 mol + 7.3 mol → 10.3 moles

Mole fraction H₂ → 3 moles / 10.3 moles = 0.29

Mole fraction = Partial pressure of the gas / Total pressure

0.29 . 304 kPa = Partial pressure of H₂ → 88.5 kPa

5 0

4 years ago

A gas has a pressure of 7.01 atm at 227°C. What will its temperature be if the pressure is increased to 12.1 atm and volume is h

kirill [66]

Answer:

The temperature of the gas will be 590.05 C.

Explanation:

Gay-Lussac's law can be expressed mathematically as follows:

$\frac{P}{T} =k$

Where P= Pressure, T = temperature, K = Constant

This law indicates that the ratio between pressure and temperature is constant.

This law indicates that, as long as the volume of the container containing the gas is constant, as the temperature increases, the gas molecules move faster. Then the number of shocks against the walls increases, that is, the pressure increases. That is, the gas pressure is directly proportional to its temperature.

In short, when there is a constant volume, as the temperature increases, the gas pressure increases. And when the temperature decreases, gas pressure decreases.

It is desired to study two different states, an initial state and an final state. You have a gas that is at a pressure P1 and at a temperature T1 at the beginning of the experiment. When the temperature varies to a new T2 value, then the pressure will change to P2, and the following will be true:

$\frac{P1}{T1} =\frac{P2}{T2}$

In this case:

P1= 7.01 atm
T1= 227 C= 500 K (being 0 C= 273 K)
P2= 12.1 atm
T2= ?

Replacing:

$\frac{7.01 atm}{500 K} =\frac{12.1 atm}{T2}$

Solving:

$T2=12.1 atm*\frac{500 K}{7.01 atm}$

T2= 863.05 K= 590.05 C

The temperature of the gas will be 590.05 C.

6 0

3 years ago

If you are doing stoichiometry and it asks you to go from grams of one substance to grams of a new substance, how many steps (ho

Thepotemich [5.8K]

Answer:

a.

c

d

a

d

i think it is it or east be responsible

make me the brainyst please

5 0

3 years ago

Given that the approximate bond length of o–h in water is roughly 1 å, what is the approximate distance each proton "hops" betwe

Ksenya-84 [330]

The hydrogen bond is a comparatively weak interaction between a proton hop and an electronegative atom present in a molecule. The hydrogen bond plays a very important role for the determination of state of a compound like gaseous, liquid or solid. The strength of the hydrogen bond depends on the close distance between the participants i.e. the electronegative atom and proton hop. There remains strong hydrogen bond between the two water molecules which is expressed as O....H. The distance of the hydrogen bond is 1.8A° formed between each proton hops of two neighboring water molecules. The hydrogen bond interaction is shown in the figure.

6 0

3 years ago

1. From the following standard electrochemical potential (and your knowledge of biomedically important metals), answer the quest

Monica [59]

Answer:

The following answer are based only on emf values

a).Most anodic element ,Titanium - Ti

b).Metal That will corrode easily is : Titanium - Ti

c). Most reactive metal is Titanium-Ti

d).Al can't be used for making implants because it undergo corrosion easily and do not form strong passive oxide layer.

Ti forms very strong passive layer which prevents further corrosion.

Au is least reactive and does not corrode.

Note : You have to give answer according to E values

In actual(without considering E values) most anodic, reactive , corrosive element is Al

Explanation:

Here the oxidation potential data is given (since elements are getting oxidised)

$\Delta^{0} E$ : Standard Reduction Potential : It is tendency of the element to gain electron and get reduced.

Oxidation Potential is opposite to reduction potential

Standard Oxidation Potential :It is tendency of the element to loose electron and get oxidised.

It is measured in Volts/V

More positive (greater)the value of the oxidation potential , stronger is the tendency of the element to get oxidised.
More negative(lesser) the value of oxidation potential lesser the tendency of the element to get oxidised. Hence the element undergo Reduction in comparison to other with more positive value .

The main application $\Delta^{0} E$ values is in electrochemical cell to predict the products of the reaction. or predict whether the reaction is spontaneous or not.

Anodic means tendency to undergo oxidation

Since $Ti\rightarrow Ti^{+}$ has maximum value of $\Delta^{0}E$ = 2.00V , so it get oxidised as compared to other elements.

Corrode , The metal which oxidise easily will also undergo corrosion easily

From the , E values Ti show maximum tendency of oxidation hence it also get corroded easily.

Ti is the most reactive because it oxidised fast as compare to other elements
Au (gold) is the least reactive element as its $\Delta^{0}E$ value is negative. So gold don't get corrode and used for making implants. Ti can also be used , since it is most reactive so it react with oxygen present in atmosphere and form a passive layer of oxide which prevent its corrosion. Al also form passive oxide but form very thin layer which is not able to protect it from corrosion

4 0

4 years ago