3 years ago

Rank the following elements in INCREASING Atomic Radius: Fe, Ni, K, Ti (SMALLEST TO

Chemistry

1 answer:

Hitman42 [59]3 years ago

8 0

B don’t tell me how ik Bc I don’t

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At a certain temperature the rate of this reaction is second order in SO3 with a rate constant of 1.18·M-1s-1 :2SO3(g)--> +2S

sergejj [24]

Answer:

Explanation:

For second order reaction

dC / dt = -k C²

dC /C² = - kdt

Integrating on both sides,

[- 1/C ] = - kt + P , P is a constant .

When t =0 , C = 1.33 M

P = - 1 / 1.33

[- 1/C ] =- - kt - 1 / 1.33

When t = 8.5

[- 1/C ] = - kt - 1 / 1.33

= - 1.18 x 8.5 - 1 / 1.33

= - 10.03 - .7519

= - 10.782

C = .0927 M

= .093 M

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What are the coefficients needed to balance this chemical reaction to show that matter is conserved?

Degger [83]

The answer is B I had took that last year

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Question 3

sashaice [31]

Answer:

Explanation:

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Which of the following values would you expect for the ratio of half-lives for a reaction with starting concentrations of 0.05M

harkovskaia [24]

Answer:

The expected ratio of half-lives for a reaction will be 5:1.

Explanation:

Integrated rate law for zero order kinetics is given as:

$k=\frac{1}{t}([A_o]-[A])$

$[A_o]$ = initial concentration

[A]=concentration at time t

k = rate constant

if, $[A]=\frac{1}{2}[A_o]$

$t=t_{\frac{1}{2}}$ , the equation (1) becomes:

$t_{\frac{1}{2}}=\frac{[A_o]}{2k}$

Half life when concentration was 0.05 M= $t_{\frac{1}{2}}$

Half life when concentration was 0.01 M= $t_{\frac{1}{2}}'$

Ratio of half-lives will be:

$\frac{t_{\frac{1}{2}}}{t_{\frac{1}{2}}'}=\frac{\frac{[0.05 M]}{2k}}{\frac{[0.01 M]}{2k}}=\frac{5}{1}$

The expected ratio of half-lives for a reaction will be 5:1.

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3 years ago