Explanation:
The nuclear reaction is a radioactive decay by the emission of a beta particle.
Beta emission increases the mass number of a nuclei.
A beta particle is a particle that closely resembles an electron. When a particle decays by emitting beta particles, the mass number remains the same but the atomic number increases.
Beta particle is designated as °₋₁β
²³₁₀ Ne ⇒ ²³₁₁Na + °₋₁β + energy
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A. Smell (Oder) B. Color and D I’m pretty sure because the common properties are Color, Oder, Melting point, and boiling point
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Answer:</h3>
43.33 atm
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Explanation:</h3>
We are given;
Mass of C₆H₆ = 26.2 g
Volume of the container = 0.25 L
Temperature = 395 K
We are required to calculate the pressure inside the container;
First, we calculate the number of moles of C₆H₆
Molar mass of C₆H₆ = 78.1118 g/mol.
But; Moles = mass ÷ Molar mass
Moles of C₆H₆ = 26.2 g ÷ 78.1118 g/mol.
= 0.335 moles C₆H₆
Second, we calculate the pressure, using the ideal gas equation;
Using the ideal gas equation, PV = nRT , Where R is the ideal gas constant, 0.082057 L.atm/mol.K
Therefore;
P = nRT ÷ V
= (0.335 mol × 0.082057 × 395 K) ÷ 0.25 L
= 43.433 atm
Therefore, the pressure inside the container is 43.33 atm
Na2CO3 mol = mass/rfm
= 91.9 / ( 23+23+12+16+16+16)
= 91.9/106
=919/1060 or roughly 0.867
Mole ratio of sodium carbonate to calcium carbonate is 1:1
Therefore calcium carbonate mol = mass/rfm
919/1060 = mass / (40+12+16+16+16)
919/1060 = mass / 100
Mass = 919/1060 x 100
= 4595/53 or 86.7g to 3 significant figures
Answer:

Explanation:
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In this case, according to the required half-reaction, we start by setting it up from bismuth (V) oxide ion to bismuth (III) ion:

Thus, next realize that the oxidation state of Bi in BiO3^- is 5+ because oxygen is 2- (-2*3+x=-1;x=-1+6;x=+5), so we obtain:

Thereafter, we realize three water molecules are needed on the right in order to balance the oxygens and consequently 6 hydrogen atoms on the left to balance hydrogen:

Now, since the balance is is basic media, we add six molecules of hydroxide ions in order to produce water with the hydrogen ones:

Then, we accommodate the waters to obtain:

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