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Kamila [148]
3 years ago
15

For the chemical reaction Na 2 CO 3 + Ca ( NO 3 ) 2 ⟶ CaCO 3 + 2 NaNO 3 how many moles of calcium carbonate will be produced fro

m 91.9 g of sodium carbonate? moles of calcium carbonate:
Chemistry
1 answer:
sp2606 [1]3 years ago
7 0
Na2CO3 mol = mass/rfm
= 91.9 / ( 23+23+12+16+16+16)
= 91.9/106
=919/1060 or roughly 0.867

Mole ratio of sodium carbonate to calcium carbonate is 1:1

Therefore calcium carbonate mol = mass/rfm

919/1060 = mass / (40+12+16+16+16)
919/1060 = mass / 100
Mass = 919/1060 x 100
= 4595/53 or 86.7g to 3 significant figures
You might be interested in
6.50 g of a certain Compound x, known to be made of carbon, hydrogen and perhaps oxygen, and to have a molecular molar mass of 1
gayaneshka [121]

Answer:

C_{10}H_8

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to find the molecular formula of the given compound by firstly calculating both moles and grams of carbon in carbon dioxide and hydrogen in water, as the only sources of these elements derived from the compound x due to its combustion:

n_C=22.35gCO_2*\frac{1molCO_2}{44.01gCO_2}*\frac{1molC}{1molCO_2}=0.51molC\\\\m_C=0.51molC*\frac{12.01gC}{1molC}   =6.10gC

n_H=3.66gH_2O*\frac{1molH_2O}{18.02gH_2O}*\frac{2molH}{1molH_2O}=0.41molH\\\\m_H=0.41molH*\frac{1.01gH}{1molH}=0.41g

Now, since the addition of carbon and hydrogen is about 6.50 grams, we infer the compound has no oxygen, that is why we now set the mole ratios in the empirical formula for both C and H as shown below:

C:\frac{0.51mol}{0.41mol}= 1.24\\\\H:\frac{0.51mol}{0.51mol}= 1\\\\C_{1.24}H

Yet it cannot be decimal, that is why we multiply by 4 to get the correct whole-numbered empirical formula:

C_5H_4

Whose molar mass is 64.09 g/mol, which makes the ratio of molar masses:

\frac{128.g/mol}{64.09g/mol} =2

Therefore, the molecular formula is twice the empirical one:

C_{10}H_8

Regards!

8 0
3 years ago
I have a question on my Chem homework. It's asking "How many molecules of N2O4 are in 76.3 g N2O4? The molar mass of N2O4 is 92.
evablogger [386]
Here, Molar mass of N2O4 = 92.02 g/mol
So, Number of molecules in 1 mole (92.02 g) = 6.023 * 10²³
Number of molecules in 76.3 g = 6.023 * 10²³ / 92.02  * 76.3
= 6.023 * 10²³ / 1.20
= 5 * 10²³ 

In short, Your Answer would be approx. 5 * 10²³ molecules

Hope this helps!
7 0
4 years ago
What is the molecular formula of paradichlorobenzene that has a molar mass of 147.g/mol and an empirical formula of C3CIH2?
Gwar [14]

Answer:

the molecular formula of paradichlorobenzene is C6H4CL2

6 0
3 years ago
Please help I need it
lubasha [3.4K]

Answer : The structure are shown below and the number of stereoisomers are possible in 3,5-dimethylnonane and 3,7-dimethyle-5-ethyldecane are 4 and 8 respectively.

Explanation :

Chiral carbon : It is carbon which is attached to the different types of atoms or molecules.

The number of stereoisomers possible for a compound is related to the number of chiral centers (n) present in it as,

\text{Number of stereoisomers}=2^n

where,

'n' is the number of chiral carbon present in the compound.

The number of chiral carbon present in 3,5-dimethylnonane is, 2 that means n = 2 (carbon-3 and carbon-5)

\text{Number of stereoisomers}=2^n=2^2=4

The number of stereoisomers are possible in 3,5-dimethylnonane is, 4

The number of chiral carbon present in 3,7-dimethyle-5-ethyldecane is, 3 that means n = 3 (carbon-3, carbon-5 and carbon-7)

\text{Number of stereoisomers}=2^n=2^3=8

The number of stereoisomers are possible in 3,7-dimethyle-5-ethyldecane is, 8

4 0
3 years ago
Help plz!!!!!!!!!! Urgent
monitta

Answer:

Explanation:

10^-2

6 0
3 years ago
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