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Llana [10]
3 years ago
15

12 rows with 14 seeds in April and 8 rows with 12 seats in each row if 272 band members purchase all the seeds in the selection

will there be enough seats for everyone explain
Mathematics
1 answer:
AleksandrR [38]3 years ago
7 0

Answer:

  not enough seats

Step-by-step explanation:

12 rows of 14 seats is ...

  12 × 14 seats = 168 seats

8 rows of 12 seats is ...

  8 × 12 seats = 96 seats

Then the total number of seats is ...

  168 seats + 96 seats = 264 seats

This is fewer than 272, so there will not be enough seats for everyone.

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Which decimal is equivalent to 8/45?
Vilka [71]

Answer:

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6 0
3 years ago
Approximately 5% of calculators coming out of the production lines have a defect. Fifty calculators are randomly selected from t
baherus [9]

Answer:

0.2611 = 26.11% probability that exactly 2 calculators are defective.

Step-by-step explanation:

For each calculator, there are only two possible outcomes. Either it is defective, or it is not. The probability of a calculator being defective is independent of any other calculator, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

5% of calculators coming out of the production lines have a defect.

This means that p = 0.05

Fifty calculators are randomly selected from the production line and tested for defects.

This means that n = 50

What is the probability that exactly 2 calculators are defective?

This is P(X = 2). So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{50,2}.(0.05)^{2}.(0.95)^{48} = 0.2611

0.2611 = 26.11% probability that exactly 2 calculators are defective.

3 0
3 years ago
Write the next three terms of the arithmetic sequence.<br> First term: 2<br> Common difference: 13
IRINA_888 [86]
15, 28, 41.

add the common difference to each consecutive term to find the next term in the sequence.

2+ 13= 15
15+ 13= 28
28+ 13= 41
4 0
3 years ago
Special right traingles (30, 60, 90<br> 45, 45, 90
igor_vitrenko [27]

Answer:

30

Step-by-step explanation:

3 0
4 years ago
Daniel’s school is selling tickets to the annual talent show. On the first day of ticket sales, the school sold 8 senior citizen
zavuch27 [327]

Answer:

the answer is 17

Step-by-step explanation:

You divide 8 and 136 and get 17, you multiply 17 and 8 to double check your answer, Hope this helps :P!

3 0
3 years ago
Read 2 more answers
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