Answer:
the first one is protons and electrons the second one is protons the third one is neutrons and the forth one is also neutron
Answer:
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Answer:
Option C (1.2 L) is the correct option.
Explanation:
The given values are:
Pressure,
![P_1=1.9 \ atm](https://tex.z-dn.net/?f=P_1%3D1.9%20%5C%20atm)
![P_2=3.8 \ atm](https://tex.z-dn.net/?f=P_2%3D3.8%20%5C%20atm)
Volume,
![V_1=2.3 \ L](https://tex.z-dn.net/?f=V_1%3D2.3%20%5C%20L)
![V_2=?](https://tex.z-dn.net/?f=V_2%3D%3F)
As we know,
The gas equation is:
⇒ ![PV=nRT](https://tex.z-dn.net/?f=PV%3DnRT)
At constant temperature,
⇒ ![P_1 V_1=P_2 V_2](https://tex.z-dn.net/?f=P_1%20V_1%3DP_2%20V_2)
or,
⇒ ![V_2=\frac{P_1 V_1}{P_2}](https://tex.z-dn.net/?f=V_2%3D%5Cfrac%7BP_1%20V_1%7D%7BP_2%7D)
By substituting the values, we get
⇒ ![=\frac{1.9\times 2.3}{3.8}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B1.9%5Ctimes%202.3%7D%7B3.8%7D)
⇒ ![=\frac{4.37}{3.8}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B4.37%7D%7B3.8%7D)
⇒ ![=1.15 \ L](https://tex.z-dn.net/?f=%3D1.15%20%5C%20L)
or,
⇒ ![=1.2 \ L](https://tex.z-dn.net/?f=%3D1.2%20%5C%20L)