Answer:
No observable change, unless dry hydrogen Chloride reacted in presence of a peroxide (ROOR)
Answer:
pOH = 5.961
Explanation:
To find the pH of a weak base we can use Henderson-Hasselbalch equation for weak bases:
pOH = pKb + log [(CH₃)₃NHCl] / [(CH₃)₃N]
<em>Where pKb is -log Kb = 4.187 and [] could be taken as moles of each specie.</em>
<em />
<em>Moles (CH₃)₃NHCl:</em>
0.0441L * (0.15mol/L) = 6.615x10⁻³moles
<em>Moles (CH₃)₃N:</em>
0.0233L * (0.16mol/L) = 3.728x10⁻³moles
And pOH is:
pOH = pKb + log [(CH₃)₃NHCl] / [(CH₃)₃N]
pOH = 4.187 + log [6.615x10⁻³moles] / [3.728x10⁻³moles]
<h3>pOH = 5.961</h3>
<em />
I think it might be 2 but I could be mistaken sorry if I am
<span>A population of the frogs that do not receive the UV radiation would work as a good control group. In this case, since the impact of the radiation is the variable under study, a group that receives no radiation, and thereby should not exhibit a change, would be a control group that could be compared against the frogs that do receive the radiation.</span>
So the whole point is that you need a abstract.
