Answer:
<em>C. 2.00 x 1023 molecules</em>
Explanation:
Given , the pressure , volume and temperature are same in both cases.
From the ideal gas equation,
P V = n R T
where n= no. of moles = given weight ÷ atomic weight
And 6.023 x 10^23 molecules of ammonia(NH3), weigh 17g ( 14 + 3(1 ))
So we have
P V = ((2.00 x 10^23)/(6.023 x 10^23)) x R T
Similarly, say <em>n</em> molecules of argon gas (Ar) are in an identical container.
So the gas equation would be
P V = ( n / 6.023 x 10^23 ) x R T
Because, atomic weight of Argon is beared by 6.023 x 10^23 molecules.
dividing these two equations, we get
n = 2.00 x 10^23 molecules
