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3 years ago

Pls help I will give brainlist

Chemistry

1 answer:

frez [133]3 years ago

5 0

Answer:

I would say B but i am not sure hope it helps

Explanation:

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Which statement best describes the properties of ionic compounds????

oksano4ka [1.4K]

Hello.

The answer is that these properties are brittle, solid at room temperature, and have a high melting point.

5 0

3 years ago

Zn + 2HCl → ZnCl2 + H2

sveticcg [70]

Answer:

Explanation:

6.0mol ( 1 mol H2/ 1 mol Zn ) = 6.0 mol of H2

H2 is hydrogen gas (hydrogen in the air).

4 0

3 years ago

A new penny has a mass of 2.49 grams and occupies 0.349 cm cubed. If pure copper has a density of 8.96 g/cm cubed, is the new pe

lys-0071 [83]

Answer: The new penny is not pure copper

Explanation:

Density $\rho$ is defined as a relation between the mass $m$ and the volume $V$ :

$\rho=\frac{m}{V}$

Now, we are told the density of pure copper is:

$\rho_{copper}=8.96 g/cm^{3}$

And we are given the mass and volume of the new penny, with which we can calculate its density:

$\rho_{penny}=\frac{m_{penny}}{V_{penny}}=\frac{2.49 g}{0.349 cm^{3}}$

$\rho_{penny}=7.13 g/cm^{3}$ As we can see the density of this penny is not equal to the density of pure copper, hence the new penny is not pure copper.

8 0

4 years ago

Identify the reaction type of the chemical reaction below. Check all that apply.

Ilya [14]

Answer:

The type of reaction is a single-replacement reaction.

Explanation:

Mg switches places with H, leaving H by itself.

8 0

3 years ago

3. The molar volume of a gas at STP occupies 0 1 kilopascal O ooc 12 grams 22.4 L

Reil [10]

The molar volume of a gas at STP occupies 22.4 L.

Option D

Explanation:

To find the volume of 1 mole of a gas at STP, we use the Ideal Gas Law. It is the general gas equation which gives the relation to the measurable quantities to an ideal gas as below,

P (pressure) × V (volume) = n (number of moles) × R (the gas constant) × T (temperature in Kelvin)

STP = 1 atm of pressure and 273 K for temperature

P = 1 atm

V = ?

n = 1 mole

R = 0.0821 atm L/mol K

T = 273 K

Using the equation,

$\mathrm{PV}=\mathrm{nRT}$

$V=\frac{n R T}{P}$

By substituting the above values, in the equation,

$V=\frac{1 \times 0.082 \times 273}{1}=22.38\ L$

V = 22.38 L

8 0

3 years ago