Which molecule has a tetrahedral arrangement of electron pairs but is not tetrahedral molecule

Chemistry

2 answers:

raketka [301]2 years ago

8 0

methane

Which molecule has a tetrahedral arrangement of electron pairs but is not a tetrahedral molecule? methane

Alex73 [517]2 years ago

7 0

Ur-Mo-M! HBAHHAHAVHSHS

You might be interested in

When the following equation is balanced, the coefficient of water is

Genrish500 [490]

Answer:

Explanation:

it make the correction

5 0

2 years ago

What is unique about the size and location of this exoplanet?

swat32

Answer:

It is the smallest planet found in the habitable zone.

Explanation:

3 0

2 years ago

Unstable isotopes undergo radioactive decay. what occurs during radioactive decay?

mel-nik [20]

Here is what radioactive decay is:
<span>Radioactive decay is the spontaneous breakdown of an atomic nucleus resulting in the release of energy and matter from the nucleus. Remember that a radioisotope has unstable nuclei that does not have enough binding energy to hold the nucleus together.</span>

5 0

3 years ago

The energy required to ionize boron is 801 kJ/mol. You may want to reference (Pages 93 - 98) Section 2.5 while completing this p

earnstyle [38]

Answer:

The frequency is $f = 2,01 * 10^{15} \ Hz$

Explanation:

From the question we are told that

The energy required to ionize boron is $E_b = 801 KJ/mol$

Generally the ionization energy of boron pre atom is mathematically represented as

$E_a = \frac{E_b}{N_A}$

Here $N_A$ is the Avogadro's constant with value $N_A = 6.022*10^{23}$

$E_a = \frac{801}{6.022*10^{23}}$

=> $E_a = 1.330 *10^{-18} \ J/atom$

Generally the energy required to liberate one electron from an atom is equivalent to the ionization energy per atom and this mathematically represented as

$E = hf = E_a$