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mihalych1998 [28]

2 years ago

7

3) g(n) = 2n h(n) = n² + 5 Find (g + h)(n)

1 answer:

elena55 [62]2 years ago

6 0

(g + h)(n) =
g(n) + h(n) =
2n + n^2 + 5 =
n^2 + 2n + 5 (standard form)

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All together, 3 people have 120 coins. mark has 3 times as many as joel, and joel has 1/2 as many as sandra. how many coins does

oksano4ka [1.4K]

Joel = j, Mark = m, Sandra = s
j + m + s = 120
m = 3j
j = 1/2 s --> s = 2j
plug in (substitute) each letter to make it in terms of only j: j + m + s = 120
j + 3j + 2j = 120
6j = 120
6j/6 = 120/6
j = 20
now plug in for the j & s equation:
s = 2j = 2(20) = 40
Therefore Sandra has 40 coins!

7 0

3 years ago

Please help with this math equation

Naily [24]

Answer: 1725 ft^2

Step-by-step explanation:

Rectangle part is 30*50 or l*w = 1500

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8 0

2 years ago

Find the sum of the terms.

kow [346]

Answer:

C

Step-by-step explanation:

Given

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= $\frac{x}{(x+1)(x+2)}$ + $\frac{3}{x+1}$

Multiply the numerator/ denominator of second fraction by (x + 2)

= $\frac{x}{(x+1)(x+2)}$ + $\frac{3(x+2)}{(x+1)(x+2)}$

The denominators are now common, so add the numerators leaving the denominator, that is

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3 years ago

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Alexeev081 [22]

Answer:

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5 0

3 years ago

The average thickness of books on a library shelf is 8.3 centimeters. The standard deviation is 0.6 centimeter. If 20% of the bo

jeka57 [31]

Answer:

8.8 cm

Step-by-step explanation:

-We know that the top 20% of the books are oversized.

-We therefore find the z-value of the top 20%:

$z_{0.1}=8.4$

#We substitute the z value in formula to solve X.

$z=\frac{\bar X-\mu}{\sigma}$

Where

X is the minimum thickness of the book.

-Given $\sigma=0.6 \ , \mu=8.3$ , the minimum thickness,X can be calculated as follows:

$z=\frac{\bar X-\mu}{\sigma}\\\\0.84=\frac{\bar X-8.3}{0.6}\\\\\bar X=0.84\times 0.6+8.3\\\\=8.804\approx 8.8\ cm$

Hence, the minimum thickness of the oversized books is 8.8 cm

3 0

3 years ago