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adoni [48]
3 years ago
14

the length of a side of a square is 10x+4 units. If the perimeter is 96 units. What is the area of the square?​

Mathematics
1 answer:
dmitriy555 [2]3 years ago
4 0

Answer:

576 Units

Step-by-step explanation:

The way your teacher wants you to do it:

1. We know that multiplying a length by four gives us the perimeter of a square.

1a. Thus, we multiply the given length by four. 4(10x+4)=40x+16

1b. We know the perimeter is 96. So: 40x+16=96

2. Solving for x, we get x=2

3. Plugging our solved x into the given length  (10x+4), we see that the length of a side of the square is 10*2+4=24.

4. We know that the area of a square can be found by squaring the side of a square.

4a. 24*24=576.

5. The area is 576 units.

--------------------------------------------------------------

Easier Solution:

1. We know that the perimeter is length*4.

2. We set L to length.

2a. 4L=96

2b. L=24

3. We know that the length square is area.

4. 24*24=576.

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nadya68 [22]
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30                 28


30 is bigger than 28.  Therefore 5/7 is greater than 4/6

Yes 5/7 is greater than 4/6.

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3 years ago
The diameter of a wheel of a car is 30cm. If the car travels at an average speed of 13.2m/s, find the number of revolutions made
Marysya12 [62]

Answer:

Approximately 50420 revolutions (rounded to the nearest whole number.)

Step-by-step explanation:

Convert the diameter of this wheel to meters: d = 30\; \rm cm = 0.30\; \rm m.

Circumference of this wheel:

\pi \, d = \pi \times 0.30\; \rm m \approx 0.942\; \rm m.

Distance travelled in one hour:

\begin{aligned}v \cdot t &= 13.2 \; \rm m \cdot s^{-1} \times 3600\; \rm s \\ &= 47520\; \rm m\end{aligned}.

Number of revolutions required for covering that distance:

\displaystyle \frac{47520\; \rm m}{(\pi \times 0.30\; \rm m)} \approx 50420.

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