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Keith_Richards [23]
2 years ago
15

Help please no links or I’ll report

Mathematics
1 answer:
vfiekz [6]2 years ago
8 0

Answer. the answer for the problem you asked is A

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Fill in the missing information. Tim Worker is doing his budget. He discovers that the average miscellaneous expense is $45.00 w
nlexa [21]

Answer:

P(38.6

And we can assume a normal distribution and then we can solve the problem with the z score formula given by:

z=\frac{X -\mu}{\sigma}

And replacing we got:

z=\frac{38.6- 45}{16}= -0.4

z=\frac{57.8- 45}{16}= 0.8

We can find the probability of interest using the normal standard table and with the following difference:

P(-0.4

Step-by-step explanation:

Let X the random variable who represent the expense and we assume the following parameters:

\mu = 45, \sigma 16

And for this case we want to find the percent of his expense between 38.6 and 57.8 so we want this probability:

P(38.6

And we can assume a normal distribution and then we can solve the problem with the z score formula given by:

z=\frac{X -\mu}{\sigma}

And replacing we got:

z=\frac{38.6- 45}{16}= -0.4

z=\frac{57.8- 45}{16}= 0.8

We can find the probability of interest using the normal standard table and with the following difference:

P(-0.4

6 0
3 years ago
Find the angle between the given vectors. Round your answer, in degrees, to two decimal places. u=⟨2,−6⟩u=⟨2,−6⟩, v=⟨4,−7⟩
NISA [10]

Answer:

\theta = 108.29

Step-by-step explanation:

Given

u =

v =

Required:

Calculate the angle between u and v

The angle \theta is calculated as thus:

cos\theta = \frac{u.v}{|u|.|v|}

For a vector

A =

A = a * b

cos\theta = \frac{u.v}{|u|.|v|} becomes

cos\theta = \frac{.}{|u|.|v|}

cos\theta = \frac{2*6+4*-7}{|u|.|v|}

cos\theta = \frac{12-28}{|u|.|v|}

cos\theta = \frac{-16}{|u|.|v|}

For a vector

A =

|A| = \sqrt{a^2 + b^2}

So;

|u| = \sqrt{2^2 + 6^2}

|u| = \sqrt{4 + 36}

|u| = \sqrt{40}

|v| = \sqrt{4^2+(-7)^2}

|v| = \sqrt{16+49}

|v| = \sqrt{65}

So:

cos\theta = \frac{-16}{|u|.|v|}

cos\theta = \frac{-16}{\sqrt{40}*\sqrt{65}}

cos\theta = \frac{-16}{\sqrt{2600}}

cos\theta = \frac{-16}{\sqrt{100*26}}

cos\theta = \frac{-16}{10\sqrt{26}}

cos\theta = \frac{-8}{5\sqrt{26}}

Take arccos of both sides

\theta = cos^{-1}(\frac{-8}{5\sqrt{26}})

\theta = cos^{-1}(\frac{-8}{5 * 5.0990})

\theta = cos^{-1}(\frac{-8}{25.495})

\theta = cos^{-1}(-0.31378701706)

\theta = 108.288386087

<em></em>\theta = 108.29<em> (approximated)</em>

4 0
2 years ago
Which of the following lines has a zero slope?
Pavlova-9 [17]

It should be A because C cannot exist at the moment. B and D are clearly slopes, so it has to be A.

7 0
3 years ago
One garden had 5 times as many raspberry bushes as a second garden. After 22 bushes are transplanted from the first garden to th
Aleonysh [2.5K]

Let the number of raspberry bushes in one garden = x

And the number of raspberry bushes in second garden = y

Garden one has 5 times as many raspberry bushes as second garden,

So the equation will be,

x = 5y -------(1)

If 22 bushes were transplanted from garden one to the second, number of bushes in both the garden becomes same,

Therefore, (x - 22) = (y + 22)

x - y = 22 + 22

x - y = 44 ------(2)

Substitute the value of x from equation (1) to equation (2)

5y - y = 44

4y = 44

y = 11

Substitute the value of 'y' in equation (1),

x = 5(11)

x = 55

Therefore, Number of bushes in garden one were 55 and in second garden 11 originally.

Learn more,

brainly.com/question/12422372

5 0
3 years ago
A survey of 898 U.S. VCR owners found that 16% had VCR clocks that were currently blinking “12:00.” (Source: Wirthlin Worldwide)
Tanya [424]
Use form f (x)=P(1+r)^x
8 0
3 years ago
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