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polet [3.4K]
3 years ago
6

Fill in the chart, find the nth term (algebraic expression) and write the pattern rule

Mathematics
1 answer:
lisov135 [29]3 years ago
8 0

Answer:

e

Step-by-step explanation:

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Which options could be the next step in simplifying this expression? 5 • (2 + 4) Choose exactly two answers that are correct. A.
Pavel [41]
5 * (2 + 4)

5 * 2 + 5 * 4 (the distributive property)
5 * 6 (order of operations)
5 0
3 years ago
How many numbers are 10 units from 0 on the number line? Type your answer as a numeral.How many numbers are 10 units from 0 on t
hammer [34]
2 numbers are 10 units from 0.  If you start from zero and count 10 units  to the right, you should be at a positive number.  But, you can also move 10 units to the left. If you do this, you should be at a negative number that  is ALSO 10 units away from 0, just in a different direction than positive number. both are 10 units from 0.   There always 2 numbers, one 10 units to the right of zero, and one 10 units to the left of zero. Hope this helped!  Tell me if I'm wrong or right. :)
                
7 0
3 years ago
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How to solve 6y-12x=24 for y
serg [7]
6y- 12x =24
6y= 24+12x
y=4+2x
4 0
3 years ago
15, Evaluate 6 choose 4.
Novosadov [1.4K]

Answer:  The required result is 15.

Step-by-step explanation:  We are given to evaluate the following :

"6 choose 4".

Since we are to choose 4 from 6, so we have to use the combination of 6 different things chosen 4 at a time.

We know that

the formula for the combination of n different things chosen r at a time is given by

^nC_r=\dfrac{n!}{r!(n-r)!}.

For the given situation, n = 6  and  r = 4.

Therefore, we get

^6C_4=\dfrac{6!}{4!(6-4)!}=\dfrac{6!}{4!2!}=\dfrac{6\times5\times4!}{4!\times2\times1}=15.

Thus, the required result is 15.

4 0
3 years ago
6 people consists of 3 married couples. Each couple wants to sit with older partner on the left.
Lera25 [3.4K]

a. The first part asks for how many ways they can be seated together in a row. Therefore we want the permutations of the set of 6 people, or 6 factorial,

6! = 6 * 5

= 30 * 4

= 360 * 2 = 720 possible ways to order 6 people in a row

b. There are two cases to consider here. If the doctor were to sit in the left - most seat, or the right - most seat. In either case there would be 5 people remaining, and hence 5! possible ways to arrange themselves.

5! = 5 * 4

= 20 * 3

= 120 * 1 = 120 possible ways to arrange themselves if the doctor were to sit in either the left - most or right - most seat.

In either case there are 120 ways, so 120 + 120 = Total of 240 arrangements among the 6 people if the doctor sits in the aisle seat ( leftmost or rightmost seat )

c. With each husband on the left, there are 3 people left, all women, that we have to consider here.

3!  = 3 * 2 6 ways to arrange 3 couples in a row, the husband always to the left

8 0
3 years ago
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