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3 years ago

6

Fill in the chart, find the nth term (algebraic expression) and write the pattern rule

1 answer:

lisov135 [29]3 years ago

8 0

Answer:

e

Step-by-step explanation:

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Refer to the accompanying data set and construct a % confidence interval estimate of the mean pulse rate of adult females; the

ivolga24 [154]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The 95% confidence interval of mean pulse rate for adult female is $71.98 < \mu < 79.88$

The 95% confidence interval of mean pulse rate for adult male is $62.89 < \mu < 70.57$

The correct option is C

Step-by-step explanation:

Generally the sample mean for Male pulse rate is mathematically represented as

$\= x_1 = \frac{\sum x_i }{n}$

= > $\= x_1 = \frac{81 + 74 + \cdots + 59 }{40 }$

= > $\= x_1 = 66.73$

Generally the standard deviation for male pulse rate is mathematically represented as

$\sigma_1 = \sqrt{\frac{\sum (x - \= x)^2 }{n-1 } }$

=> $\sigma_1 = \sqrt{\frac{\sum (81 - 66.73 )^2 + (74 - 66.73 )^2+ \cdot + (59 - 66.73 )^2 }{40-1 } }$

=> $\sigma_1 = 12.24$

From the question we are told the confidence level is 95% , hence the level of significance is

$\alpha = (100 - 95 ) \%$

=> $\alpha = 0.05$

Generally from the normal distribution table the critical value of $\frac{\alpha }{2}$ is

$Z_{\frac{\alpha }{2} } = 1.96$

Generally the margin of error is mathematically represented as

$E = Z_{\frac{\alpha }{2} } * \frac{\sigma_1 }{\sqrt{n} }$

=> $E = 1.96 * \frac{12.4 }{\sqrt{40} }$

=> $E =3.84$

Generally 95% confidence interval is mathematically represented as

$\= x_1 -E < \mu < \=x_1 +E$

=> $66.73 -3.84 < \mu < 66.73 +3.84$

=> $62.89 < \mu < 70.57$

Generally the sample mean for Female pulse rate is mathematically represented as

$\= x_2 = \frac{\sum x_i }{n}$

= > $\= x_2 = \frac{81 + 94 + \cdots + 73 }{40 }$

= > $\= x_2 = 75.93$

Generally the standard deviation for Female pulse rate is mathematically represented as

$\sigma_2 = \sqrt{\frac{\sum (x - \= x)^2 }{n-1 } }$

=> $\sigma_2 = \sqrt{\frac{\sum (81 - 66.73 )^2 + (94 - 66.73 )^2+ \cdot + (73 - 66.73 )^2 }{40 } }$

=> $\sigma_2 = 12.73$

Generally from the normal distribution table the critical value of $\frac{\alpha }{2}$ is

$Z_{\frac{\alpha }{2} } = 1.96$

Generally the margin of error is mathematically represented as

$E = Z_{\frac{\alpha }{2} } * \frac{\sigma_2 }{\sqrt{n} }$

=> $E = 1.96 * \frac{12.73 }{\sqrt{40} }$

=> $E =3.95$

Generally 95% confidence interval is mathematically represented as

$\= x_2 -E < \mu < \=x_2 +E$

=> $75.93 -3.95 < \mu < 75.93 + 3.95$

=> $71.98 < \mu < 79.88$

8 0

3 years ago

Plz help me, I'm too stupid to know this answer

katrin [286]

Answer:

The answer is the second one

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

IRISSAK [1]

Answer:

15 seventh graders

Step-by-step explanation:

1/5 of 75 is 15

6 0

3 years ago

Read 2 more answers

$3.68÷17= step by step

Mnenie [13.5K]

Three ventilation fans, each working alone, can clear the smoke out of a room in 12 hours, 16 hours, and 24 hours respectively. How long would it...

8 0

3 years ago

There are blue, red and green pencils in the box—20 pencils total. There are 6 times more green pencils than blue pencils. There

lana [24]

Answer:

You have to take 15 pens to get at least one red pencil.

Step-by-step explanation:

If there were one red and 6 green pens, there would be more red than green pens.

If there were 3 or more blue and thus 18 or more green pens, the number of pens would be over 20.

So there must be 2 blue, 12 green and thus 6 red pencils. So you have to take at least 15 pens to be sure that you got a red one.

5 0

3 years ago