i'm pretty sure the slope is zero ...
Sin2(x) +cos(x)=1
from the relation: (sin2(x) +cos2(x) =1 )
so , sin2(x)=1-cos2(x)
by subs. in the main eqn.
1-cos2(x) + cos(x) =1
by simplify the eqn.
cos(x) -cos2(x)=0
take cos(x) as a common factor
cos(x)* (1-cos(x))=0
then cos(x)=0 && cos(x)=1
cos(x)=0 if x= pi/2
& cos(x) = 1 if x = 0 , 2*pi
so the solution is x= {0,pi/2 , 2*pi}
A+5=5a+5 Subtract a from each side
5=5a+5 Subtract 5 from each side
0=5a Divide each side by the number before the variable to get it alone.
--- ---
5 5
a=0
Answer:
The graph you have is wrong. This is the right graph.
Hope this helps! Have a nice day, good luck, and stay safe!