How many molecules are there in 10 grams of N2I6?

What is the new concentration of a solution of CaSO3 if 10.0 mL of a 2.0 M CaSO3 solution is diluted to 100 ml?

kifflom [539]

Answer: The new concentration of a solution of $CaSO_{3}$ is 0.2 M 10.0 mL of a 2.0 M $CaSO_{3}$ solution is diluted to 100 mL.

Explanation:

Given: $V_{1}$ = 10.0 mL, $M_{1}$ = 2.0 M

$V_{2}$ = 100 mL, $M_{2}$ = ?

Formula used to calculate the new concentration is as follows.

$M_{1}V_{1} = M_{2}V_{2}$

Substitute the values into above formula as follows.

$M_{1}V_{1} = M_{2}V_{2}\\10.0 mL \times 2.0 M = M_{2} \times 100 mL\\M_{2} = 0.2 M$

Thus, we can conclude that the new concentration of a solution of $CaSO_{3}$ is 0.2 M 10.0 mL of a 2.0 M $CaSO_{3}$ solution is diluted to 100 mL.

5 0

2 years ago

What is a difference between an atom and a molecule.....???? (Plz follow me)

Misha Larkins [42]

Answer:

An atom is the smallest particle of an element that can take part in a chemical reaction while a molecule is a group of chemically combined atoms.

Explanation:

8 0

2 years ago

If a sample of radioactive isotopes takes 60 minutes to decay from 200 grams to 50 grams, what is the half-life of the isotope

qaws [65]

Answer:

I HOPE IT WILL BE YOUR ANSWER:

Explanation:

As given

60 min = 50 gm (1)

then we know half-life mean half amount decay time

so we can write as the half of 200 is 100 gm hence

T 1/2 = 100 (2)

solving these two equation by cross multiplication we will get

T 1/2 = 120 min

THANKS FOR ASKING QUESTION

6 0

3 years ago

If you burn 23.4 g of hydrogen and produce 209 g of water, how much oxygen reacted?

Kitty [74]

The chemical reaction is expressed as:

2H2 + O2 = 2H2O

To determine the amount of oxygen used in the reaction, we use the amount of water produced and the relation of the substances in the reaction we do as follows:

209 g H2O ( 1 mol / 18.02 g ) ( 1 mol O2 / 2 mol H2O ) ( 32 g / 1 mol ) = 185.57 g O2

6 0

3 years ago

A compound made of elements A and B, has a cubic unit cell. There is an A atom at each corner of the cube and an A atom at the c

Lorico [155]

Answer:

A₅B₄

Explanation:

Since we have one atom of element A at the center of each face of the unit cell, since the unit cell is a cubic cell, we have 6 faces. Since the atom on the face of the unit cell is shared with another cell, we have half of it in the unit cell is shared So, the number of atoms per face is 1/2 atom/face × 6 faces = 4 atoms on the faces of the unit cell.

Also, we have 1 atom at each corner of the cubic unit cell. Since there are 8 corner in the cubic unit cell. Also, each atom at the corner is shared with 8 unit cells, so we have 1/8 atom per corner. So, the number of atoms per unit cell is 1/8 atom/corner × 8 corners = 1 atoms at the corners of the unit cell.

So, in total we have 4 + 1 = 5 atoms of element A in the unit cell.

Also, there are 4 atoms of element B in the unit cell.

So, the ratio of atoms of element A to element B is 5 : 4.

A:B = 5:4

So, the empirical formula of the compound containing elements A and B is A₅B₄

5 0

2 years ago