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MAVERICK [17]
3 years ago
8

CH3CH2CH2CH2CH2CH3 + Br2 →

Chemistry
1 answer:
vlada-n [284]3 years ago
8 0

Answer:

2 \sqrt{1176} \\mi infierno:v

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3 years ago
The filling of which orbital is represented by the transition metals in period 4?
Sindrei [870]

Answer: 3d

Explantion:

1) Period 4 contains the elements with atomic numbers 19 through 36.

2) The elements with atomic numbers 19 (K) and 20 (Ca) fill the orbital 4s.

3) After that, as Aufbau's rule may help you to remember, the energy of the orbitals 3d is lower than the energy of the orbtitals 4p. So, the element 21 (Sc) start fillind the orbital 3d.

There are ten 3d orbitals, so the elements 21 through 30 fill the 3d orbitals.

Those elements, called transition metals are: Sc, Ti, V, Cr, Mn, Fe, Co, Ni, Cu, and Zn.

When the 3d orbitals are full, the next elements in the same period 4, fill the six 4p orbitals.

3 0
3 years ago
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The boiling point of an aqueous 1.83 m (nh4)2so4 (molar mass = 132.15 g/mol) solution is 102.5°c. determine the value of the van
Goshia [24]

We need to know the value of van't hoff factor.

The van't hoff factor is: 2.66 or 2.7 (approximately)

(NH₄)₂SO₄ is an ionic compound, so it dissociates in solution and produces 3 ionic species. Therefore van't hoff factor is more than one.

From the equation: ΔT_{b}=i K_{b}.m, where ΔT_{b}= elevation of boiling point=102.5 - 100=2.5°C.

m=molality of solute=1.83 m (Given)

K_{b}= Ebullioscopic constant or Boiling point elevation constant= 0.512°C/m (Given)

i= Van't Hoff factor

So, 2.5= i X 0.512 X 1.83

i=\frac{2.5}{0.512 X 1.83}

i=2.66= 2.7 (approx.)


6 0
3 years ago
In the scientific method, analysis should follow right after
alina1380 [7]
Observation/ question
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7 0
3 years ago
Answering questions by analyzing specific observations and using them to come to a more general understanding is known as ______
ad-work [718]

The correct answer would be inductive reasoning.

Primavera?

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3 years ago
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