Garden one and two are both unknown, so I am choosing to call garden 2 X and then label garden 1 with comparisons to X.
It is tempting to list:
Garden Two = X
Garden One = X + 9
BUT there is an easier way. We are told that when 3 bushes are taken from garden 2 (x-3) and put in garden 1 (x + 12) then garden one has 1.5 times more than garden two.
Set it up like this:
1.5 ( x - 3) = x + 12 (because 1.5 times garden 2 will give us garden 1)
1.5x - 4.5 = x + 12 (Distribute)
.5x = 16.5 (Use subtraction to move variables to the right and other numb left)
x = 33 for Garden 2
33 + 9 for Garden 1 = 42
We let
a1 = first term
a2 = second term
a3 = third term
and so on
We are given with
a1 + a2 = 26
S5 (sum of five terms) = 35
The formula for the sum of terms is
Sn = (a1 + an) (n/2)
SO
35 = (a1 + a5) (5/2)
The formula for an arithmetic term is
an = a1 + d(n-1)
For
a2 = a1 + d
we know that
a1 + a2 = 26
Simply for a1, a2, and d. Then use the formula to get the other items asked.
If two planes are perpendicular, they intersect. if two planes are parallel, they will never touch. hope this helps
The value of cumulative frequency is the sum of all previous frequencies. We should have 26 at the end of the table because all frequency add up to 26
To graph the cumulative frequency, we would need the plots.
Use the end of value range against the cumulative frequency valueRange 40-49, use the value 49 against the cumulative frequency 1
(49, 1)(59, 3)(69, 5)(79, 12)(89, 21)(99, 26)
Plot these on graph and connect them as a curve.
Answer:
X=-12
Step-by-step explanation:
Subtract -5/2 on both sides:
X/3+5/2-5/2=-3/2-5/2
X/3=-8/2
X/3=-4
Multiply both sides by 3:
X/3*3=-4*3
X=-12
