The attendance at two baseball games on successive nights was 74,000. The attendance on Thursday's game was 4,000 more than two-
1 answer:
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Answer:
V=15.44
Step-by-step explanation:
We have a formula
V=\int^{π/3}_{-π/3} A(x) dx ,
where A(x) calculate as cross sectional.
We have:
Inner radius: 5 + sec(x) - 5= sec(x)
Outer radius: 7 - 5=2, we get
A(x)=π 2²- π· sec²(x)
A(x)=π(4-sec²(x))
Therefore, we calculate the volume V, and we get
V=\int^{π/3}_{-π/3} A(x) dx
V=\int^{π/3}_{-π/3} π(4-sec²(x)) dx
V=[ π(4x-tan(x)]^{π/3}_{-π/3}
V=π·(8π/3-2√3)
V=15.44
We use a site geogebra.org to plot the graph.
we have
The solution is the shaded area above the dotted line
we know that
If a point is a solution of the inequality, then the coordinates of the point must satisfy the inequality
We will verify all cases to determine the solution of the problem
<u>Case A)</u> Point
Substitute the value of x and y in the inequality and verify
-------> is not true
therefore
the point is not a solution of the inequality
<u>Case B)</u> Point
Substitute the value of x and y in the inequality and verify
-------> is true
therefore
the point is a solution of the inequality
<u>Case C)</u> Point
Substitute the value of x and y in the inequality and verify
-------> is not true
therefore
the point is not a solution of the inequality
<u>Case D)</u> Point
Substitute the value of x and y in the inequality and verify
-------> is not true
therefore
the point is not a solution of the inequality
therefore
<u>the answer is the Point B</u>
To better understand the problem see the attached figure
