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Schach [20]
3 years ago
15

Onny wants to buy a guitar that costs $600. He makes $2 per day. How many days will it take Onny to save enough money to buy the

guitar?
Mathematics
1 answer:
lana66690 [7]3 years ago
4 0

Answer:

300 days

Step-by-step explanation:

What you have to do is divide 600/2. Then you get 300.

Hope it helped :)

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Find the circumference and the area of a circle with radius 7 yd . Use the value 3.14 for π , and do not round your answers. Be
Elina [12.6K]
7•2=14
3.14•14=
Answer: 43.96 yds
(I hope this help :) sorry if I’m incorrect)
7 0
3 years ago
Suppose you work in the quality assurance department of a chemical processing plant and it is your responsibility to ascertain w
aleksandrvk [35]

Answer:

48.668 ≤ μ ≤ 63.332

Step-by-step explanation:

Given the data:

Sample (X) : 71, 45, 54, 75, 50, 49, 63, 55, 48, 50

Number of samples (n) = 10

α = 95% = 0.05

Determine the range within which the true mean of the fluid samples from the day shift will be with a 95% confidence

True mean = μ

Confidence interval :

m ± t(α/2 ; df) * s/√n

m - t(α/2 ; df) * s/√n ≤ μ ≤ m + t(α/2 ; df) * s/√n

m = sample mean ; s = sample standard deviation ; df = degree of freedom =(n - 1) = (10 - 1) = 9

Calculating the sample mean and standard deviation using calculator to save computation time :

71, 45, 54, 75, 50, 49, 63, 55, 48, 50

m = 56 ; s = 10.25

m - t(0.05/2 ; 9) * s/√n ≤ μ ≤ m + t(0.05/2 ; df) * s/√n

From t table : t(0.05/2 ; 9) = t(0.025, 9) = 2.262

56-2.262 * (10.25/√10) ≤ μ ≤ 56+2.262 * (10.25/√10)

48.668 ≤ μ ≤ 63.332

6 0
3 years ago
The weight of a Great blue heron, a type of bird, can grow to around 4 pounds, but can vary. Let W be a random variable that rep
hammer [34]

Answer:

10 ≥  w  ≥  9 ( ? )

Step-by-step explanation:

the probability that a Great blue heron is at least 9 pounds, but no more than 10 pounds         ->      w= weight of great blue heron

w is at lest 9 pound's ->   w ≥ 9

w is no more than 10 pound's ->   w ≥ 10

w ≥  9 ( + )  w ≥  10    =     10 ≥  w ≥  9

6 0
3 years ago
Una caja de 25 newtons se suspende mediante un cable con diámetro de 2cm¿cuál es el esfuerzo aplicado al cable?
Naddik [55]

El cable experimenta un esfuerzo axial de 79577.472 pascales por el peso de la caja.

<h3>¿Cómo calcular el esfuerzo aplicado sobre el cable?</h3>

La caja tiene masa y está sometida a un campo gravitacional, por tanto, tiene un peso (W), en newtons. Por el principio de acción y reacción (tercera ley de Newton), encontramos que el cable es tensionado debido a ese peso y su área transversal experimenta un esfuerzo axial (σ), en pascales.

Asumiendo una distribución uniforme de la fuerza sobre toda la superficie transversal de la cuerda, tenemos que el esfuerzo axial se calcula mediante la siguiente expresión:

σ = W / (π · D² / 4)

Donde:

  • W - Peso de la caja, en newtons.
  • D - Diámetro del área transversal de la caja, en metros.

Si sabemos que W = 25 N y D = 0.02 m, entonces el esfuerzo axial aplicado a la cuerda es:

σ = 25 N / [π · (0.02 m)² / 4]

σ ≈ 79577.472 Pa

<h3>Observación</h3>

La falta de problemas verificados en español sobre esfuerzos axiales obliga a buscar uno equivalente en inglés.

Para aprender más sobre esfuerzos axiales: brainly.com/question/13683145

#SPJ1

5 0
1 year ago
Tam multiplied 2.13 and 4.62, as shown. But he forgot to put a decimal point in his
yuradex [85]
The decimal gives after the 9. There are four places behind the decimal between the two numbers being multiplied so there have to be 4 places behind the decimal in your answer.
8 0
2 years ago
Read 2 more answers
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