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krek1111 [17]
3 years ago
7

10 Kg box rest on 30 degree incline and begins to slide down.(a) What is the acceleration if no friction is present?(b) What is

the acceleration if the coefficient of kinetic friction is 0.2?(c) What is the final speed of box when it reaches the bottom of an incline that is 200 m length? (use the acceleration in part b)
Physics
1 answer:
kobusy [5.1K]3 years ago
3 0

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A speed-time graph shows a car moving at 10 m/s for 10 s. The cars speed constantly decreases until it comes to a stop at 30 s.
Ray Of Light [21]

speed of the car at t = 10 s is given as 10 m/s

now at t = 30 s car comes to rest so v = 0

now in this velocity time graph we can say slope will show the acceleration of the car as we know that acceleration is rate of change in velocity

a = \frac{v_f - v_i}{\Delta t}

as we know that

v_f = 0

v_i = 10 m/s

\Delta t = (30 - 10) = 20 s

now from above formula

a = \frac{0 - 10}{20} = -0.5 m/s^2

So slope of the graph will represent the acceleration of car which is 0.5 m/s^2

5 0
3 years ago
Read 2 more answers
I just don't know how to do the question (a) and (b)​
ozzi

Using the equation

F=ma

we can observe that you have to apply a non-zero net force to an object in order to make it accelerate. In fact, if the net force is zero you have

0=ma \iff a=0

Since we're assuming n\neq 0

Now, if the 12N force is applied, the object moves with a constant speed. A constant speed means no acceleration, since by definition the acceleration is a change in speed.

If this sounds counterintuitive to you (why I'm applying a force but I have to acceleration?) think of when we drive a car: even if you want to keep your speed constant, you still have to use the gas pedal, just enough so that the push of the motor balances exactly the road/wheels friction. If you give less gas, the friction becomes stronger, and the car slows down. If you give more gas, the motor push becomes stronger, and the car accelerates.

Back to your exercise: constant speed means to acceleration, so the net force must be zero. This implies that the friction force is exactly 12N.

If the force is increased to 18N, there will be a net force of 6N pushing the object, causing it to accelerate. Using again the same equation of before, and plugging the 3kg mass in the equation, we have

F=ma \iff 6=3a \iff a=2

So, the object moves with constant acceleration and initial speed of 10m/s for 0.2 seconds. It's final speed will be

v = v_0+at = 10+2\cdot 0.2 = 10.4

5 0
3 years ago
A. How does doubling the height of the cylinder affect its GPE?
vampirchik [111]

The answer would be:

Doubling the height will increase the amount of Joules produced.


8 0
3 years ago
Marys airplane trip took 5.8 hours for one-half of that time, the airplane flew at a constant speed of 640 miles per hour and fo
Olenka [21]
Distance is speed x time.  Half of the trip is 5.8/2 = 2.9hrs.
640 x 2.9 = 1856mi
580 x 2.9 = 1682mi
1856mi+1682mi=3538mi.

You could also calculate her average speed.  This is easy since it was divided in two equal time slices.  Average Speed = (640+580)/2 = 610mi/hr
Now 610mi/hr x 5.8hrs = 3538mi
7 0
3 years ago
Which of these statements best proves that electromagnetic forces are weaker than strong nuclear forces? Neutrons do not repel o
MAVERICK [17]
Protons do not move out of the nucleus of atoms although they repel each other.

Remember that protons are particles with positive charge and they held together in the nucleus of the atom which is a tiny tiny region. As you know, like charges repel each other, which means that the protons exert a repulsion force.
8 0
3 years ago
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