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krek1111 [17]
3 years ago
7

10 Kg box rest on 30 degree incline and begins to slide down.(a) What is the acceleration if no friction is present?(b) What is

the acceleration if the coefficient of kinetic friction is 0.2?(c) What is the final speed of box when it reaches the bottom of an incline that is 200 m length? (use the acceleration in part b)
Physics
1 answer:
kobusy [5.1K]3 years ago
3 0

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NemiM [27]
Lever: a bar used to move something
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Incline plane : a ramp it’s used to help rise heavy things
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8 0
2 years ago
Read 2 more answers
If six moles of hydrogen chloride (HCl) react with plenty of aluminum, how many moles of aluminum chloride (AlCl3) will the reac
AlexFokin [52]

Answer:

Two moles of aluminum chloride (AlCl_3) are produced when six miles of hydrogen Chloride (HCl) react with plenty of aluminum

Explanation:

6 Moles of HCl will only react with 2 moles of Al irrespective of the number of moles of each compound present. The reaction wiil take place in this ratio only. The products produced will be 2 moles of AlCl_3 and 3 moles of H_2 this ratio will also be constant.

So, six moles of hydrogen chloride (HCl) will react with plenty of aluminum to produce many 2 moles of aluminum chloride (AlCl_3).

5 0
2 years ago
Determine the energy in joules of a photon whose frequency is 3.55 x10^17 hz
asambeis [7]
By using the Plancks-Einstein equation, we can find the energy;
E = hf
where h is the plancks constant = 6.63 x 10⁻³⁴
f = frequency = 3.55 x 10¹⁷hz
E = (6.63 x 10⁻³⁴) x (3.55 x 10¹⁷)
E = 2.354 x 10⁻¹⁶J
3 0
3 years ago
A man runs 1200m on a straight line in 4 min . find his velocity.
luda_lava [24]

Answer:

5m/sec^2

Explanation:

Distance=1200m

Time=4 min

1=60sec

4=4 x 60

=240sec

Velocity=Distance/Time

Velocity=1200/240

Velocity=5m/sec^2

Mark me as brainliest

7 0
3 years ago
A 2.7-kg ball is thrown upward with an initial speed of 20.0 m/s from the edge of a 45.0 m high cliff. At the instant the ball i
scoray [572]

Answer:

The distance traveled by the woman is 34.1m

Explanation:

Given

The initial height of the cliff

yo = 45m final, positition y = 0m bottom of the cliff

y = yo + ut -1/2gt²

u = 20.0m/s initial speed

g = 9.80m/s²

0 = 45.0 + 20×t –1/2×9.8×t²

0 = 45 +20t –4.9t²

Solving quadratically or by using a calculator,

t = 5.69s and –1.61s byt time cannot be negative so t = 5.69s

So this is the total time it takes for the ball to reach the ground from the height it was thrown.

The distance traveled by the woman is

s = vt

Given the speed of the woman v = 6.00m/s

Therefore

s = 6.00×5.69 = 34.14m

Approximately 34.1m to 3 significant figures.

3 0
3 years ago
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