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Gennadij [26K]
3 years ago
13

This formula equation is unbalanced.

Physics
1 answer:
Grace [21]3 years ago
6 0
The answer is:  [C]:  "4" .
___________________________________________________
Note:  To balance this equation, the coefficient, "4", should be placed in front of the PCl₃ ;  and the coefficient, "6", should be placed in front of the Cl₂ .
________________________________________________________
The balanced equation is:
__________________________________________________
             P₄ (s) + 6 Cl₂ (g)  <span>→ 4 </span>PCl₃ (l)   .
______________________________________________________
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Explain why a doctor might not give you any medication if you have a viral disease?
fomenos

Answer:

You never know if the medication could make you worse

Explanation:

5 0
3 years ago
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A charge of 31.0 μC is to be split into two parts that are then separated by 24.0 mm, what is the maximum possible magnitude of
miskamm [114]

Answer:

1.72 x 10³ N.

Explanation:

When a charge is split equally and placed at a certain distance , maximum electrostatic force is possible.

So the charges will be each equal to

31/2 = 15.5 x 10⁻⁶ C

F = K Q q / r²

= \frac{9\times10^9\times(10.5)^2\times10^{-12}}{(24\times10^{-3})^2}

= 1.72 x 10³ N.

8 0
4 years ago
8.92 x 10 ^ 6 (convert from scientific notation to a standard aka regular number)
n200080 [17]
The answer is 8,920,000

7 0
3 years ago
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Can classical physics be used to accurately describe a satellite moving at a speed of 7500 m/s? explain why or why not.
gogolik [260]

The classical physics works on the Newton's laws of motion. It is applicable on heavenly bodies which are governed by the gravitational force. On the other hand, Quantum Physics is applicable for very low mass and sized bodies like electron, protons etc. The classical physics would accurately describe the motion of satellite moving with speed 7500 m/s using the following formula:

r=\frac {GM}{v^{2}}

where G is the gravitational constant, M is the mass of the planet and v is the orbital speed. Then radius of the orbit can be described by this formula.

3 0
3 years ago
a chuck wagon with an initial velocity of 4 m/s and a mass of 35 kg gets a push with 350 joules of force. what is the wagon's fi
Kitty [74]

Answer:

the final velocity of the wagon is 6 m/s.

Explanation:

Given;

initial velocity of the wagon, u = 4 m/s

mass of the wagon, m = 35 kg

energy applied to the wagon, E = 350 J

The final velocity of the wagon is calculated as;

E = ¹/₂m(v² - u²)

m(v^2-u^2) = 2E\\\\v^2-u^2 = \frac{2E}{m} \\\\v^2 =  \frac{2E}{m}  + u^2\\\\v = \sqrt{\frac{2E}{m}  + u^2} \\\\v = \sqrt{\frac{2(350)}{35}  + (4)^2}\\\\v = 6 \ m/s

Therefore, the final velocity of the wagon is 6 m/s.

8 0
3 years ago
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