Answer:
I think deposition of C is the oldest deposit
The answer is; 2.
To balance a chemical equation, the moles on one side of the equation has to be the same as that on the other side. This ensures that the law of conservation is observed because matter or energy can't be created or destroyed but can only be transformed from one form to another.
In this equation, putting 2 in front of NaCl ensures that there are 2 moles of Na and CL just as there are 2 moles of Na and CL in the reactants side.
Answer:
3.33m/s
Explanation:
Speed is the change in distance of a body with respect to time.
Speed = Distance/Time
Given
Distance = 1100m
Time = 330s
Speed = 1100/330
Speed = 3.33m/s
Hence her average speed in m/s is 3.33m/s
Oh what a sneaky problem !
The "range" of a projectile is how far out away from the gun it goes
before it falls to the ground.
The question is asking you: "What angle should you aim the gun
above the horizon so that the bullet doesn't go <em>any</em> distance away
from the gun, and it hits the ground exactly where the gun is "
And there are two different answers. Really sneaky !
Can you think of how you could fire the gun so that the bullet would
hit the ground right under the gun ? How about pointing the gun at
the ground ... aiming 90 degrees <em>below</em> the horizon ? That would
certainly do it. Is there another way to do it ?
How about aiming the gun straight up in the air ... 90 degrees <em>above</em>
the horizon ? Then it goes up, up, up, runs out of steam, stops rising,
starts falling, comes down, down, down, and hits the ground right where
the gun was.
As long as there's no air and no wind, the two angles are +90 degrees
and -90 degrees above the horizon.
' +90 above ' means straight up. ' -90 above ' means straight down.
The final velocity of the skateboarder I after the collision is 3 m/s to the left.
<h3>
Velocity of skateboarder I</h3>
The velocity of skateboarder I is determined from the principle of conservation of linear momentum.
m1u1 + m2u2 = m1v1 + m2v2
50(0) + 75(0) = 50v1 + 75(2)
0 = 50v1 + 150
v1 = (-150)/50
v1 = - 3
v1 = 3 m/s to the left
Thus, the final velocity of the skateboarder I after the collision is 3 m/s to the left.
Learn more about linear momentum here: brainly.com/question/7538238
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