Step-by-step explanation:
We are asked to simply (2√5 + 3√2)². Using formula: (a + b)² = a² + b² + 2ab. Let's say 2√5 = a, 3√2 = b. So,
→ (a + b)² = a² + b² + 2ab
→ (2√5 + 3√2)² = (2√5)² + (3√2)² + 2(2√5)(3√2)
We are aware about the fact that root means 1/2 and square of root means 2/2 that is 1. Using this we get:
→ (2√5 + 3√2)² = 4(5) + 9(2) + 2(2√5)(3√2)
Solve the brackets, to do so first put the like terms in one box.
→ (2√5 + 3√2)² = 4(5) + 9(2) + 2(2*3)(√5)(√2)
Solve the rest calculations.
→ (2√5 + 3√2)² = 20 + 18 + 2(6)(√10)
→ (2√5 + 3√2)² = 38 + 12√10
Option (a) (38 + 12√10) is the correct option.
Step-by-step explanation:
commutative property of multiplication
3 * 5 means 5 + 5 + 5 which equals 15.
5 * 3 means 3 + 3 + 3 + 3 + 3 which equals 15.
Parallelogram have 4 sides.
Use the distributive property. 2 multiply the last and negative 4 in the parentheses.
2l + 2(l - 4) = 72 m
Combine Like terms
2l + 2l - 8 = 72 m
4l - 8 = 72 m
Get l all by itself by adding 8 to both sides
4l - 8 = 72 m
+8. +8
Divide both sides by 4
4l = 80
4. 4
l= 20
The width of the parallelogram is four meters less than its length.
4 sides
2 length = 20
2 width = 16
I got 16 by subtracting 4 from 20
Comment if you need any other help :)
Answer:
interest rate = 2.9%
Step-by-step explanation:
the principal is $25,000, the interest is $10,875
Number of years = 15
We use simple interest formula
I = P*r*t
Where I is the interest amount=10,875
P is the principal amount= 25000
r is the interest rate = r
t is the number of years = 15
Plug in all the value in the formula
I = P*r*t
10875 = 25000 * r * 15
10875 = 375000 * r
Divide both sides by 375000
r=0.029
We always write rate of interest in percentage so we multiply by 100
0.029 * 100= 2.9%
So interest rate = 2.9%
Answer:
-816.8 ft²/min
Step-by-step explanation:
The rate of change of area is the product of the rate of change of radius and the circumference of the circle. At the time of interest, ...
dA/dt = C·dr/dt = 2πr·dr/dt
dA/dt = 2π·(26 ft)(-5 ft/min)
dA/dt = -260π ft²/min ≈ -816.8 ft²/min
