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Art [367]
3 years ago
11

6. A hypothesis test in which rejection of the null hypothesis occurs for values of the point estimator in either tail of the sa

mpling distribution is called _______ Group of answer choices A one-tailed test A two-tailed test The null hypothesis The alternative hypothesis g
Mathematics
1 answer:
natita [175]3 years ago
8 0

Answer:

A two-tailed test.

Step-by-step explanation:

ANOVA is a short term or an acronym for analysis of variance which was developed by the notable statistician Ronald Fisher. The analysis of variance (ANOVA) is typically a collection of statistical models with their respective estimation procedures used for the analysis of the difference between the group of means found in a sample. Simply stated, ANOVA helps to ensure we have a balanced data by splitting the observed variability of a data set into random and systematic factors.

In Statistics, the random factors doesn't have any significant impact on the data set but the systematic factors does have an influence.

Basically, the analysis of variance (ANOVA) procedure is typically used as a statistical tool to determine whether or not the mean of two or more populations are equal through the use of null hypothesis or a F-test.

Hence, the null hypothesis for an analysis of variance (ANOVA) requires that all treatments or samples should be generated from populations having the same mean.

A hypothesis test in which rejection of the null hypothesis occurs for values of the point estimator in either tail of the sampling distribution is called a two-tailed test.

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Step 1:

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\begin{gathered} P(t)=-15.64t^2\text{ - 1.24t + 5.2}3 \\ =\text{ -15.64 }\times0.3^2\text{ - 1.24}\times\text{ 0.3 + 5.2}3 \\ =\text{ -1.4076 - 0.372 + }5.23 \\ =\text{ 3.45} \end{gathered}

c) t = 0.52 seconds

\begin{gathered} p(t)=-15.64t^2\text{ - 1.23t + 5.23} \\ =\text{ -15.64}\times0.52^2\text{ - 1.23}\times0.52\text{ + 5.23} \\ =\text{ -4.23 - 0.64 + 5.23} \\ =\text{ 0.36} \end{gathered}

d) 0.30 is more likely to be relaible.

e)

\begin{gathered} p(t)\text{ = 1} \\ p(t)=-15.64t^2\text{ - 1.23t + 5.23} \\ 1=-15.64t^2\text{ - 1.23t + 5.23} \\ -15.64t^2\text{ - 1.23t + 4.23 = 0} \\ t\text{ = 0.48222} \\ \text{t = 0.48 seconds} \end{gathered}

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