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choli [55]
2 years ago
7

Find two consecutive negative odd integers whose product is 35?

Mathematics
2 answers:
anygoal [31]2 years ago
5 0

Answer:36

Step-by-step explanation:

katovenus [111]2 years ago
5 0

Step-by-step explanation:

let, a required negative number be x

then it's cnsecutive odd negative. be x+2

now,

x \times (  x + 2) = 35 \\ or \:  \:  {x}^{2}  \:   +  2x = 35 \\    {x}^{2}  + 2x   = 35 \\  {x}^{2}   +  2x - 35 = 0 \\  {x}^{2}   + 7x  -  5x - 35 = 0 \\ x(x  + 7)  -  5(x  +  7) = 0 \\ (x  + 7) (x  - 5) = 0 \\  \\ now \:  \:  \:  \:  \:  \:  \:either \:  \: x  +  7 = 0 \\ x =  - 7\\  \\or \:  \:  \:  \:  \: (x  - 5) = 0 \\ x  =  5

since ,

we have supposed a negative number ,

,

we need negative odd number so,

x = -7

and it's consecutive number will be x+2

so, it is. -7+2 = -5

hence ,

-7 *and -5 are the required answer.

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