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3 years ago

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Nitrogen dioxide is a red-brown gas that is responsible for the color of photochemical smog. What is the volume of 1 mol of nitr

ogen dioxide(assumed to be an ideal gas) at STP? O A. 27.6 L O B.22.4L O C. 29.6L O D. 21.8 L

1 answer:

Ray Of Light [21]3 years ago

5 0

B ideal gas has a volume of 22.4

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What is the potential energy of a molecule?

iren2701 [21]

Answer:

I guess the answer is D point

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2 years ago

Read 2 more answers

Find the volume of a box with length 25 cm, height 25 cm and width 1.0 m. Volume

mariarad [96]

The volume of a box with length 25 cm, height 25 cm and width 1.0 m is 0.0625m³.

Volume of the box which is a cuboid can be calculated by multiplying the length, breadth and height of the given box.

Volume of the box is given by the product of the length of the box, Height of the box and Breadth or width of the box.

Since, the box is a cuboid, hence the formula is given by the products of length, breadth and height.

Given,

length of the box= 25cm = 0.25m

Height of the box =25cm = 0.25m

width of the box= 1m

Volume = length × width × height of box

Volume = 0.25 × 0.25 × 1

Volume = 0.0625m³

The volume of the box is 0.0625m³.

Learn more about Volume here, brainly.com/question/23118276

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4 0

2 years ago

How many grams of Sodium metal are required to completely react with 100 g of Magnesium chloride hexahydrate in a single replace

slava [35]

Answer:

MgCl2 - 6H2O

203.3 mol

MgCl2 + 2Na = 2NaCl + Mg

22.6g

Explanation:

1. Write the formula of hydrate and find molar mass.

2. Write a balanced single replacement (don't include H2O)

3. Do the given/wanted calculation (include H2O in molar mass of given)

6 0

3 years ago

Proton-alpha: "One time I lived in an environment where next door lived identical twins, Proton-beta-1 and Proton-beta-2. Boy, d

Mashcka [7]

Answer:

Explanation:

C) What is the multiplicity of Proton-alpha's signal in this scenario when there are 2 identical protons "next door"?

Based on n+1 rule. Here n=2 (identical beta protons).

2+1=3

So the multiplicity of alpha proton is triplet, .

D) For molecules containing only single bonds (we'll discuss the influence of double bonds in a future lecture), what is the adjective that describes the position of protons that split a "next door neighbor's" signal?

The meaning of the adjective is this: the multiplicity of beta protons is singlet only (no spliting) in absence of alpha proton . But beta protons splits as doublet (n=1) in the presence of alpha proton,

E) How many bonds connect these "splitting next door neighbors"?

There are 3 bonds in between alpha and beta protons in a molecule.

F) What is the multiplicity of the Proton-betas' signal?

Following the n+1 rule, here n=1 (1 alpha proton) so 1+1=2. Hence it is a doublet.

7 0

4 years ago

Using the following portion of the activity series for oxidation half-reactions, determine which combination of reactants will r

dusya [7]

The question is incomplete, the complete question is:

Using the following portion of the activity series for oxidation half-reactions, determine which combination of reactants will result in a reaction.

$Li(s)\rightarrow Li^+(aq)+e^-$

$Al(s)\rightarrow Al^{3+}(aq)+3e^-$

A) Li(s) with Al(s)

B) Li(s) with $Al^{3+}$ (aq)

C) $Li^+$ (aq) with Al(s)

D) $Li^+$ (aq) with $Al^{3+}$ (aq)

<u>Answer: </u>The correct option is B): Li(s) with $Al^{3+}$ (aq)

<u>Explanation:</u>

The oxidation reaction is defined as the reaction in which a chemical species loses electrons in a chemical reaction.

A reduction reaction is defined as the reaction in which a chemical species gains electrons in a chemical reaction.

The chemical species will undergo a reduction reaction if the value of standard reduction potential is more positive or less negative.

For the given half-reactions:

$Li(s)\rightarrow Li^+(aq)+e^-;E^o_{Li^+/Li}=-3.04V$

$Al(s)\rightarrow Al^{3+}(aq)+3e^-;E^o_{Al^{3+}/Al}=-1.662V$

As the value of standard reduction potential of aluminium is less negative. Thus, it undergoes reduction reaction and lithium will undergo oxidation reaction.

The half-reaction follows:

<u>Oxidation half-reaction:</u> $Li(s)\rightarrow Li^+(aq)+e^-$ ( × 3)

<u>Reduction half-reaction:</u> $Al^{3+}(aq)+3e^-\rightarrow Al(s)$

<u>Overall cell-reaction:</u> $3Li(s)+Al^{3+}(aq)\rightarrow 3Li^+(aq)+Al(s)$

Hence, the correct option is B): Li(s) with $Al^{3+}$ (aq)

5 0

3 years ago