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Nataliya [291]
3 years ago
13

How many oxygen atoms are present in 22.6 grams of sulfur trioxide (SO,)? (Show work)

Chemistry
1 answer:
s2008m [1.1K]3 years ago
8 0

Answer:

Well,

3

×

N

A

oxygen atoms..

Explanation:

Where

N

A

≡

Avogadro's number

≡

6.022

×

10

23

⋅

m

o

l

−

1

.

And so if wl1

oxygen atoms...

i.e.

18.066×

1023

⋅

oxygen atoms..

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Answer:

The answer to your question is: letter c

Explanation:

Data

V1 = 612 ml    n1 = 9.11 mol

V2 = 123 ml    n2 = ?

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Explanation  

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 I  

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