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Nataliya [291]
2 years ago
13

How many oxygen atoms are present in 22.6 grams of sulfur trioxide (SO,)? (Show work)

Chemistry
1 answer:
s2008m [1.1K]2 years ago
8 0

Answer:

Well,

3

×

N

A

oxygen atoms..

Explanation:

Where

N

A

≡

Avogadro's number

≡

6.022

×

10

23

⋅

m

o

l

−

1

.

And so if wl1

oxygen atoms...

i.e.

18.066×

1023

⋅

oxygen atoms..

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(2.03x10^22)/(6.02x10^23) = .033721 mol Li

I hope this helps, if not, i am sorry

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Cu has an anomalous electron configuration. write the observed electron configuration of cu.
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What element is likely to form an ionic compound with chlorine?
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Object A at 40.°C and object B at 80.°C are placed in contact with each other. Which statement describes the heat flow between t
alukav5142 [94]

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Copper metal (Cu) reacts with silver nitrate (AgNO3) in aqueous solution to form Ag and Cu(NO3)2. An excess of AgNO3 is present.
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Stoichiometry time! Remember to look at the equation for your molar ratios in other problems.

31.75 g Cu | 1 mol Cu | 2 mol Ag | 107.9 g Ag         6851.65
⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻   →   ⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻  = 107.9 g Ag
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There's also a shorter way to do this: Notice the molar ratio from Cu to Ag, which is 1:2. When you plug in 31.75 into your molar mass for Cu, it equals 1/2 mol. That also means that you have 1 mol Ag because of the ratio, qhich you can then plug into your molar mass, getting 107.9 as well.
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3 years ago
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