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lidiya [134]
3 years ago
8

When humans burn fuel or cut down trees, they (increase/decrease) levels of carbon dioxide in the atmosphere.

Chemistry
2 answers:
Brrunno [24]3 years ago
8 0
It will increase the levels.
Arturiano [62]3 years ago
7 0
When humans burn fuel/cut down tress, they will increase the level of carbon dioxide within the atmosphere. Tress "inhale" the carbon dioxide within the atmosphere and without them, the excess will still linger. Carbon dioxide is a byproduct of burning fuel thus, it will increase the levels in the atmosphere.
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The beaker shown below contains a 0.58 M solution of dye in water. How many moles of dye are there in the beaker?
seropon [69]
According to the equation of molarity:

Molarity= no.of moles / volume per liter of Solution

when we have the molarity=0.58 M and the beaker at 150mL so V (per liter) = 150mL/1000 = 0.150 L

by substitution:
∴ No.of moles = Molarity * Volume of solution (per liter)
                        = 0.58 * 0.150 = 0.087 Moles
7 0
3 years ago
Read 2 more answers
CH4 + 202 → CO2 + 2H2O<br> How many grams of O2 needed to react with 2 moles of CH4?
PtichkaEL [24]
<h3>Answer:</h3>

100 g O₂

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table

<u>Stoichiometry</u>

  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[RxN - Balanced]   CH₄ + 2O₂ → CO₂ + 2H₂O

[Given]   2 mol CH₄

[Solve]   x g O₂

<u>Step 2: Identify Conversions</u>

[RxN] 1 mol CH₄ → 2 mol O₂

[PT] Molar Mass of O - 16.00 g/mol

Molar Mass of O₂ - 2(16.00) = 32.00 g/mol

<u>Step 3: Stoichiometry</u>

  1. Set up conversion:                     \displaystyle 2 \ mol \ CH_4(\frac{2 \ mol \ O_2}{1 \ mol \ CH_4})(\frac{32.00 \ g \ O_2}{1 \ mol \ O_2})
  2. Multiply/Divide:                           \displaystyle 128 \ g \ O_2

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 1 sig fig.</em>

128 g O₂ ≈ 100 g O₂

3 0
3 years ago
Read 2 more answers
What is the mass of 1.6x1020 molecules of carbon dioxide?
valentina_108 [34]

Answer:

1.2*10^{-2} g

Explanation:

1 mol - 6*10^{23} particles

1.6*10^{20}* \frac{1 mol}{6.02*10^{23}} = 0.00026578 mol\\\\M(CO2) = 12 + 2*32=44 \frac{g}{mol}\\

44\frac{g}{mol} *0.00026578 mol =0.012 = 1.2*10^{-2} g

8 0
3 years ago
Is O2 covalent molecular or polar covalent
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6 0
3 years ago
How many aluminum atoms are in 2.88 g of aluminum?
alex41 [277]

Answer:

Explanation:

1 Mole of Aluminum with mass 26.98g contains 6.02*10^23 atoms.

In 2.88g of Aluminum, there are 2.88/26.98*6.02*10^23 = 6.426*10^22 atoms.

8 0
3 years ago
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