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Vadim26 [7]
2 years ago
11

What is the molar mass of an unknown gas with a density of 4.95 g/L at 1.00 atm and 25.0 °C?

Chemistry
1 answer:
mestny [16]2 years ago
3 0

Answer:

121 g/mol

Explanation:

To find the molar mass, you first need to calculate the number of moles. For this, you need to use the Ideal Gas Law. The equation looks like this:

PV = nRT

In this equation,

-----> P = pressure (atm)

-----> V = volume (L)

-----> n = moles

-----> R = constant (0.0821 L*atm/mol*K)

-----> T = temperature (K)

Because density is comparing the mass per 1 liter, I am assuming that the system has a volume of 1 L. Before you can plug the given values into the equation, you first need to convert Celsius to Kelvin.

P = 1.00 atm                         R = 0.0821 L*atm/mol*K

V = 1.00 L                             T = 25.0. °C + 273.15 = 298.15 K

n = ? moles

PV = nRT

(1.00 atm)(1.00L) = n(0.0821 L*atm/mol*K)(298.15 K)

1.00 = n(0.0821 L*atm/mol*K)(298.15 K)

1.00 = (24.478115)n

0.0409 = n

Now, we need to find the molar mass using the number of moles per liter (calculated) and the density.

0.0409 moles           ? grams           4.95 grams
----------------------  x  ------------------  =   ------------------
        1 L                       1 mole                     1 L

? g/mol = 121 g/mol

**note: I am not 100% confident on this answer

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Explanation:

Given:  

Pressure = 3.04 atm

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T(K) = T( °C) + 273.15  

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T₁ = (25.0 + 273.15) K = 298.15 K  

Volume = 1.50 L

Using ideal gas equation as:

PV=nRT

where,  

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R is Gas constant having value = 0.0821 L.atm/K.mol

Applying the equation as:

3.04 atm × 1.50 L = n × 0.0821 L.atm/K.mol × 298.15 K  

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The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

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