Answer:
800 full marks
Step-by-step explanation:
295 + 25 = 320 marks required to pass
320 / 0.40 = 800 full marks
Answer:
Step-by-step explanation:
We would apply the formula for determining compound interest which is expressed as
A = P(1+r/n)^nt
Where
A = total amount in the account at the end of t years
r represents the interest rate.
n represents the periodic interval at which it was compounded.
P represents the principal or initial amount deposited
From the information given,
P = 4500
A = 6300
r = 6.75% = 6.75/100 = 0.0675
n = 2 because it was compounded 2 times in a year.
Therefore,.
6300 = 4500(1 + 0.0675/2)^2t
6300/4500 = (1 + 0.03375)^2t
1.4 = 1.03375^2t
Taking log of both sides of the equation, it becomes
Log 1.4 = 2t log 1.03375
0.1461 = 2t × 0.0144 = 0.0288t
t = 0.1461/0.0288
t = 5.1 years.
Direction: Opens Down
Vertex:
(
0
,
81
)
(0,81)
Focus:
(
0
,
323
4
)
(0,3234)
Axis of Symmetry:
x
=
0
x=0
Directrix:
y
=
325
4
y=3254
Select a few
x
x
values, and plug them into the equation to find the corresponding
y
y
values. The
x
x
values should be selected around the vertex.
Tap for more steps...
x
y
−
2
77
−
1
80
0
81
1
80
2
77
xy-277-180081180277
Graph the parabola using its properties and the selected points.
Direction: Opens Down
Vertex:
(
0
,
81
)
(0,81)
Focus:
(
0
,
323
4
)
(0,3234)
Axis of Symmetry:
x
=
0
x=0
Directrix:
y
=
325
4
y=3254
x
y
−
2
77
−
1
80
0
81
1
80
2
77
xy-277-180081180277
f
(
x
)
=
8
1
−
x
2
?
?
f(x)=81-x2??
f
(
x
)
=
81
−
x
2
x
?
f(x)=81-x2x?
f
(
x
)
=
81
−
x
2
x
2
?
f(x)=81-x2x2?
f
(
x
)
=
81
−
x
2
x
3
?
f(x)=81-x2x3?
(
)
|
[
]
√
≥
π
7
8
9
Direction: Opens Down
Vertex:
(
0
,
81
)
(0,81)
Focus:
(
0
,
323
4
)
(0,3234)
Axis of Symmetry:
x
=
0
x=0
Directrix:
y
=
325
4
y=3254
Select a few
x
x
values, and plug them into the equation to find the corresponding
y
y
values. The
x
x
values should be selected around the vertex.
Tap for more steps...
x
y
−
2
77
−
1
80
0
81
1
80
2
77
xy-277-180081180277
Graph the parabola using its properties and the selected points.
Direction: Opens Down
Vertex:
(
0
,
81
)
(0,81)
Focus:
(
0
,
323
4
)
(0,3234)
Axis of Symmetry:
x
=
0
x=0
Directrix:
y
=
325
4
y=3254
x
y
−
2
77
−
1
80
0
81
1
80
2
77
xy-277-180081180277
f
(
x
)
=
8
1
−
x
2
?
?
f(x)=81-x2??
f
(
x
)
=
81
−
x
2
x
?
f(x)=81-x2x?
f
(
x
)
=
81
−
x
2
x
2
?
f(x)=81-x2x2?
f
(
x
)
=
81
−
x
2
x
3
?
f(x)=81-x2x3?
(
)
|
[
]
√
≥
π
7
8
9
Direction: Opens Down
Vertex:
(
0
,
81
)
(0,81)
Focus:
(
0
,
323
4
)
(0,3234)
Axis of Symmetry:
x
=
0
x=0
Directrix:
y
=
325
4
y=3254
Select a few
x
x
values, and plug them into the equation to find the corresponding
y
y
values. The
x
x
values should be selected around the vertex.
Tap for more steps...
x
y
−
2
77
−
1
80
0
81
1
80
2
77
xy-277-180081180277
Graph the parabola using its properties and the selected points.
Direction: Opens Down
Vertex:
(
0
,
81
)
(0,81)
Focus:
(
0
,
323
4
)
(0,3234)
Axis of Symmetry:
x
=
0
x=0
Directrix:
y
=
325
4
y=3254
x
y
−
2
77
−
1
80
0
81
1
80
2
77
xy-277-180081180277
f
(
x
)
=
8
1
−
x
2
?
?
f(x)=81-x2??
f
(
x
)
=
81
−
x
2
x
?
f(x)=81-x2x?
f
(
x
)
=
81
−
x
2
x
2
?
f(x)=81-x2x2?
f
(
x
)
=
81
−
x
2
x
3
?
f(x)=81-x2x3?
(
)
|
[
]
√
≥
π
7
8
9
Direction: Opens Down
Vertex:
(
0
,
81
)
(0,81)
Focus:
(
0
,
323
4
)
(0,3234)
Axis of Symmetry:
x
=
0
x=0
Directrix:
y
=
325
4
y=3254
Select a few
x
x
values, and plug them into the equation to find the corresponding
y
y
values. The
x
x
values should be selected around the vertex.
Tap for more steps...
x
y
−
2
77
−
1
80
0
81
1
80
2
77
xy-277-180081180277
Graph the parabola using its properties and the selected points.
Direction: Opens Down
Vertex:
(
0
,
81
)
(0,81)
Focus:
(
0
,
323
4
)
(0,3234)
Axis of Symmetry:
x
=
0
x=0
Directrix:
y
=
325
4
y=3254
x
y
−
2
77
−
1
80
0
81
1
80
2
77
xy-277-180081180277
f
(
x
)
=
8
1
−
x
2
?
?
f(x)=81-x2??
f
(
x
)
=
81
−
x
2
x
?
f(x)=81-x2x?
f
(
x
)
=
81
−
x
2
x
2
?
f(x)=81-x2x2?
f
(
x
)
=
81
−
x
2
x
3
?
f(x)=81-x2x3?
(
)
|
[
]
√
≥
π
7
8
9
vvvvv
Answer:
3
Step-by-step explanation:
