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Mrac [35]
3 years ago
14

True Or False!....SUCROSE MOLECULES BREAK DOWN DURING CELLULAR RESPIRATION

Biology
1 answer:
nirvana33 [79]3 years ago
4 0
The answer is: False

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Step 1. A carboxyl group is removed from pyruvate, releasing a molecule of carbon dioxide into the surrounding medium. (Note: carbon dioxide is one carbon attached to two oxygen atoms and is one of the major end products of cellular respiration. ) The result of this step is a two-carbon hydroxyethyl group bound to the enzyme pyruvate dehydrogenase; the lost carbon dioxide is the first of the six carbons from the original glucose molecule to be removed. This step proceeds twice for every molecule of glucose metabolized (remember: there are two pyruvate molecules produced at the end of glycolysis); thus, two of the six carbons will have been removed at the end of both of these steps.

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3 years ago
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2 years ago
Use the terms in the answers below to fill in the blanks in the following sentences. "An investigator is studying mutants in met
Arlecino [84]

Question is incomplete i have added full question in ask for detail section.

Answer:

Option a. met3, Met3p, MET3 is correct answer

"An investigator is studying mutants in methionine synthesis. The _met3_ mutants are unable to ATP sulfurylase, also known as _Met3p_. This protein is the product of the _MET3_gene. "

Explanation:

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Source: National Center for Biotechnology Information, U.S. National Library of Medicine

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