Answer: To make protein and store hereditary information
Explanation:
Answer:
THE RELATIONSHIP OF IDENTIFICATION TO BACTERIAL CLASSIFICATION AND NOMENCLATURE. In order to identify an unknown bacterial isolate, the characteristics of the isolate must be compared to known taxa. In microbiology, the basic taxonomic unit is the species, and groups of related species are placed in the same genus.
Answer:
3/16
Explanation:
<u>According to Mendel's law of independent assortment of genes, when a dihybrid cross involves two genes that assort independently and one of the parents is dominant for the two genes and the other is recessive, the phenotypic ratio of the offspring at F2 would be 9:3:3:1</u>. The proportion of the offspring with the dominant parental traits would be 9/16, those with the recessive parental traits would be 1/16, while those with mixed traits would be 3/16 each.
Assuming the eye color is represented by E and the wing shape is represented by W. At F2
EeWw x EeWw
E_W_ - 9/16 (dominant for both eye color and wing shape)
E_ww - 3/16 (dominant for eye color and recessive for wing shape)
eeW_ - 3/16 (recessive for eye color and dominant for wing shape)
eeww - 1/16 (recessive for both eye color and wing shape)
<em>Hence, the proportion of the offspring with dominant phenotype for eye color and recessive phenotype for wing shape would be </em><em>3/16.</em>
Answer:
The bond between the _second_________ phosphate group and the third__phosphate group is a high energy bond.
Explanation:
Adenosine triphosphate is a nucleotide with three phosphate groups. The second and third phosphate groups are bonded by high energy covalent bonds to the rest of the ATP molecule, which consists of a sugar, which is ribose, the first phosphate group, and the nitrogenous base which is adenine. All of the phosphate groups are negatively charged and repel each other, so a high energy covalent bond is necessary to attach these phosphate groups together and keep the forces from pulling them apart.
