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Serggg [28]
3 years ago
5

Divide 794.1 by 7.61. Round off your answer to two decimal places. A. 1,043.50 B. 95.83 C. 104.35 D. 786.49

Mathematics
1 answer:
Tcecarenko [31]3 years ago
6 0
104.36 this is the answer
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3 years ago
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I need help with this problem, if anyone could help ASAP, that would be much appreciated. In the figure below, mROP = 125° Find
VARVARA [1.3K]

Answer:

mRP = 125°

mQS = 125°

mPQR = 235°

mRPQ = 305°

Step-by-step explanation:

Given that

  • mROP = 125°
  • ∠ROP is a central angle

Then:

  • measure of arc RP, mRP = mROP = 125°

Given that

  • ∠QOS and ∠ROP are vertical angles

Then:

  • mQOS = mROP = 125°
  • measure of arc QS, mQS = mROP = 125°

Given that

  • ∠QOR and ∠SOP are vertical angles

Then:

  • mQOR = mSOP

Given that

  • The addition of all central angles of a circle is 360°

Then:

mQOS + mROP + mQOR + mSOP = 360°

250° + 2mQOR = 360°

mQOR = (360°- 250°)/2

mQOR = mSOP = 55°

And (QOR and SOP are central angles):

  • measure of arc QR, mQR = mQOR = 55°
  • measure of arc SP, mSP = mSOP = 55°

Finally:

measure of arc PQR, mPQR = mQOR + mSOP + mQOS = 55° + 55° + 125° = 235°

measure of arc RPQ, mRPQ = mROP + mSOP + mQOS = 125° + 55° + 125° = 305°

6 0
3 years ago
Evaluate 8+3e when e= 2.
trapecia [35]

\text{Hey there!}

\text{If e = 2 then replace the e in the equation to 2}

\mathsf{8+3e}\\\mathsf{= 8+3(2)}\\\mathsf{3(2)=6}\\\mathsf{8+6=14}\\\\\boxed{\boxed{\mathsf{Answer: \boxed{\mathsf{14}}}}}\checkmark

\text{Good luck on your assignment and enjoy your day!}

~\dfrac{\frak{LoveYourselfFirst}}{:)}

5 0
2 years ago
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Write the equation for the area of a triangle with a height that is 5 more than twice its base using one variable. Please help m
zysi [14]

Answer:

A=b(b+\frac{5}{2} )

Step-by-step explanation:

hey there!!!

we know already that the area of a triangle is given as

A=\frac{1}{2}b *h

where b= base

and h= heigth

Given that the height is 5 times more than twice it base

let h= 2b+5

Now we substitute h=2b+5 in the area of the triangle

A=\frac{1}{2}b * (2b+5)

A= \frac{2b^2}{2} +\frac{5b}{2}

A= b^2+\frac{5b}{2}\\\\A=b(b+\frac{5}{2} )

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3 years ago
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The slope would be 3/4!
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