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3 years ago

11

How do you find the answer for f(5) when f(x)= -3x^4+7x^2-2

1 answer:

ololo11 [35]3 years ago

8 0

You find f(5) the same way you evaluate any function. Put the number where the variable is and do the arithmetic.

When high powers are involved, it can simplify the arithmetic a little to do some factoring:
.. f(x) = (-3x^2 +7)*x^2 -2
.. f(5) = (-3*25 +7)*25 -2 = -68*25 -2
.. f(5) = -1702

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There are 10 marbles in a paper bag, 6 of which are red. The rest are blue. You play a game with your friend. If you draw a red

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No, because you have 1 more marble than her. While you have 6 marbles in the bag, she has 4; there’s a 3/5 chance that you’ll win, and a 2/5 chance that she’ll win.

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2 years ago

Insert grouping symbols in 5 x 2 + 8 - 4 - 2 so that its value is 15

Arlecino [84]

5×2+8-4+1=15
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3 years ago

Lee watches tv 3hours per day. Lee tv consumes 200 watts when on. Electricity cost 12 cents 1 kilowatt-hour how much does Lee's

Alik [6]

Answer: $2.16

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Cost of electricity = 12 cents/(1-kilowatt-hour)

200w×3 hours

600 watt-hours

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3 0

3 years ago

Read 2 more answers

A 4-lb. force acting in the direction of (vector) 4,-2 moves an object just over 7ft from point (0,4) to (5,-1). Find the work d

Tcecarenko [31]

To solve this problem, we have to find the net displacement and the net force and the multiply the dot product together and get the work done.

The work done on moving the object is 27ft*lbs

<h3>Work done in moving the object from point A to point B</h3>

To find the work done on this object, let's find the net force on the object.

Data;

force = 4lb
direction = 4, -2
displacement = 7ft
direction = (0, 4) to (5,1)

The unit vector of the force is

$\sqrt{4^2 +(-2)^2} =\sqrt{16 + 4} = \sqrt{20}$

$\frac{4}{\sqrt{20} }, \frac{-2}{\sqrt{20} }$

The net force acting on the object is

$F = 4(\frac{4}{\sqrt{20} }, \frac{-2}{\sqrt{20} })\\F= (\frac{16}{\sqrt{20} }, \frac{-8}{\sqrt{20} } )$

The displacement on the object is 7ft through (0,4) to (5, -1)

The unit vector on displacement is

$\sqrt{5^2 + (-1-4)^2} = \sqrt{25+25} = \sqrt{50}$

$\frac{5}{\sqrt{50} }, \frac{-5}{\sqrt{50} }$

The net displacement will be

$7(\frac{5}{\sqrt{50} }, \frac{-5}{\sqrt{50} }) = \frac{35}{\sqrt{50} }, \frac{-35}{50}$

The work done will be F.d

$w = f. d \\$

$w = (\frac{16}{\sqrt{20} }, \frac{-8}{\sqrt{20} } ) * \frac{35}{\sqrt{50} }, \frac{-35}{50}\\w = 17.71+ 8.854\\w = 26.567 = 27ft*lbs$

The work done on moving the object is 27ft*lbs

Learn more on work done on an object here;

brainly.com/question/26152883

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6 0

2 years ago

kirill115 [55]

Answer:

its 4

Step-by-step explanation:

solve for y and then find the point of intersection

3 0

2 years ago