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3 years ago

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How do you find the answer for f(5) when f(x)= -3x^4+7x^2-2

1 answer:

ololo11 [35]3 years ago

8 0

You find f(5) the same way you evaluate any function. Put the number where the variable is and do the arithmetic.

When high powers are involved, it can simplify the arithmetic a little to do some factoring:
.. f(x) = (-3x^2 +7)*x^2 -2
.. f(5) = (-3*25 +7)*25 -2 = -68*25 -2
.. f(5) = -1702

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Need some help with this question please

Serggg [28]

Answer:

$\frac{15}{17}$

Step-by-step explanation:

$\cos( \alpha ) = \frac{ad}{hip} \\ \\ \sin( \alpha ) = \frac{op}{hip}$

Pythagorean theorem

hip² = op² + ad²

17² = x² + 8²

x² = 17² - 8²

$x \: = \sqrt{{17}^{2} - {8}^{2} } \\ x = \sqrt{289 - 64} \\ x = \sqrt{225} \\ x = 15$

$\sin( \alpha ) = - \frac{15}{17}$

$\sin( - \alpha ) = \frac{15}{17}$

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2 years ago

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kherson [118]

Answer: 40

Step-by-step explanation:

138/x = 207/60

8280 = 207x

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3 years ago

7p²-30p + 8 how do you factor this trinomial

tamaranim1 [39]

Step-by-step explanation:

7p²-30p+8

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3 years ago

Write a system<br> of linear inequalities represented by the graph.

Helga [31]

2,3 or 4,1 either one

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2 years ago

A random sample of 23 items is drawn from a population whose standard deviation is unknown. The sample mean isx⎯ ⎯ x¯ = 840 and

gayaneshka [121]

Answer:

$(832.156, \ 847.844)$

Step-by-step explanation:

Given data :

Sample standard deviation, s = 15

Sample mean, $\overline x = 840$

n = 23

a). 98% confidence interval

$\overline x \pm t_{(n-1, \alpha /2)}. \frac{s}{\sqrt{n}}$

$$E= t_{( n-1, \alpha/2 )} \frac{s}{\sqrt n}}$

$t_{(n-1 , \alpha/2)} \frac{s}{\sqrt n}$

$t_{(n-1, a\pha/2)}=t_{(22,0.01)} = 2.508$

∴ $E = 2.508 \times \frac{15}{\sqrt{23}}$

$E = 7.844$

So, 98% CI is

$(\overline x - E, \overline x + E)$

$(840-7.844 , \ 840+7.844)$

$(832.156, \ 847.844)$

4 0

2 years ago