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3 years ago

10

An electron enters a region of uniform perpendicular en and bn fields. it is observed that thevelocity nv of the electron is una

ffected. a possible explanation is:

1 answer:

konstantin123 [22]3 years ago

5 0

<span>v is perpendicular to both E and B and has a magnitude E/B</span>

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A 0.15 kg ball is moving with a velocity of<br> 35 m/s. Find the momentum of the ball.

GarryVolchara [31]

Answer:

<h2>5.25 kg.m/s</h2>

Explanation:

The momentum of an object can be found by using the formula

momentum = mass × velocity

From the question we have

momentum = 0.15 × 35

We have the final answer as

<h3>5.25 kg.m/s</h3>

Hope this helps you

4 0

3 years ago

A force, F1, of magnitude 2.0 N and directed due east is exerted on an object. A second force exerted on the object is F2 = 2.0

IgorLugansk [536]

Answer:

Magnitude of the force is

$F_3 = 2.83$

direction of the force is given as

$\theta = 45 degree$ West of South

Explanation:

As we know that force is a vector quantity and in order to find the resultant of two or more forces we need to add them vectorialy

So here we have

$\vec F_1 + \vec F_2 + \vec F_3 = 0$

here we know that first force is of magnitude 2 N towards east

$\vec F_1 = 2 \hat i N$

second force is also of 2.0 N due North

$\vec F_2 = 2 \hat j$

now from above equation

$2\hat i + 2\hat j + \vec F_3 = 0$

$\vec F_3 = -2\hat i - 2\hat j$

so magnitude of the force is given as

$F_3 = \sqrt{2^2 + 2^2}$

$F_3 = 2.83$

direction of the force is given as

$\theta = tan^{-1}\frac{F_y}{F_x}$

$\theta = tan^{-1}\frac{-2}{-2}$

$\theta = 45 degree$ West of South

3 0

3 years ago

Read 2 more answers

A high frequency sound wave corresponds to high _____.

lina2011 [118]

A highly frequency sound wave corresponds to a high pitch sound

6 0

3 years ago

A 6-in-wide polyamide F-1 flat belt is used to connect a 2-in-diameter pulley to drive a larger pulley with an angular velocity

Likurg_2 [28]

Answer:

a) Fc = 4.15 N, Fi = 435.65 N, (F1)a = 640 N, and F2 = 239.6 N,

b) Ha = 1863.75 N, nfs = 1 , length = 11.8 mm

Explanation:

Given that:

γ= 9.5 kN/m³ = 9500N/m3

b = 6 inches = 0.1524 m

t = 0.0013 mm

d = 2 inches = 0.0508 m

n = 1750 rpm

$H_{nom}=2hp=1491.4W$

L = 9 ft = 2.7432 m

Ks = 1.25

g = 9.81 m/s²

a)

$w=\gamma b t = 9500* 0.1524*0.0013=1.88N/m$

$V=\frac{\pi d n}{60} =\pi *0.0508*1750/60=4.65 m/s$

$F_c=\frac{wV^2}{g}=1.88*4.65^2/9.81=4.15N$

$(F_1)_a=bF_aC_pC_v=0.1524*6000*0.7*1=640N$

$T=\frac{H_{nom}n_dK_s}{2\pi n}= \frac{1491*1.25*1}{2*\pi*1750/60}=10.17Nm$

$F_2=(F_1)_a-\frac{2T}{D}= 640-\frac{2*10.17}{0.0508} =239.6N$

$F_i=\frac{(F_1)_a+F_2}{2} -F_c=435.65N$

b)

$H_a=1491*1.25=1863.75W$

$n_f_s=\frac{H_a}{H_{nom}K_S }=1$

dip = $\frac{L^2w}{8F_i} =\frac{2.7432*1.88}{435.65}=11.8mm$

7 0

3 years ago

What is the pressure of the gas in this mercury manometer if h = 89 mm and atmospheric pressure is 775 mmhg?

ludmilkaskok [199]

The pressure of the gas is 686 mmhg.
If h = 89 mm
and atmospheric pressure = 775 mmhg
Pressure of the gas = ?
We can find the pressure of the gas by finding the difference between both values.
pressure of the gas = 775 mmhg - 89 mm = 686 mmhg

6 0

4 years ago

Read 2 more answers