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ANEK [815]
3 years ago
8

It’s either A or B but idk, i’ll give brainliest :)

Mathematics
1 answer:
forsale [732]3 years ago
3 0

Answer:

Actually it's A.

Step-by-step explanation:

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Sin 0 = -3/5<br> and cos 0 &gt; 0. Identify the quadrant of the terminal side of O and find cos 0.
NARA [144]

Answer:

See below.

Step-by-step explanation:

Cos O is positive in the first and 4th quadrants and sin O is negative in the 3rd and 4th quadrants.

So the answer is Quadrant 4.

cos^2 O = 1 - sin^2 O

= 1 - (-3/5)^2

= 16/25

So  cos O  is +√(16/25)

= 4/5.

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2 years ago
PLEASEEW HELPPP WILL MARK BRAINLEST !!pntss
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Answer:

the correct answer is choice 2

Step-by-step explanation:

reason being that both bc and ac would both be vertical lines so they have the same slope of undefined

8 0
3 years ago
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What is the balance as a result of having a credit of $84 and a debit of $29
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6 0
3 years ago
What is the value of the equation -2/3x + 9 = 4/3 x -3?​
MArishka [77]

Answer:

x = 6

Step-by-step explanation:

\frac{-2}{3}x+9=\frac{4}{3}x-3\\\\\frac{-2}{3}x-\frac{4}{3}=-3-9\\\\\frac{-2-4}{3}x= - 12\\\\\frac{-6}{3}x = -12\\\\ -2x  -12\\\\x = \frac{-12}{-2}\\\\x = 6

3 0
3 years ago
All cars can be classified into one of four​ groups: the​ subcompact, the​ compact, the​ midsize, and the​ full-size. There are
Olegator [25]

Answer:

p value = 0.302

Step-by-step explanation:

Given that all cars can be classified into one of four​ groups: the​ subcompact, the​ compact, the​ midsize, and the​ full-size. There are five cars in each group. Head injury data​ (in hic) for the dummies in the​ driver's seat are listed below.

H_0: All cars have same mean values

H_a: atleast two cars have different mean values

(Two tailed anova test)

Anova: Single Factor      

     

SUMMARY      

Groups Count Sum Average Variance  

Subcompact 5 3444 688.8 48502.7  

compact 5 2879 575.8 4582.7  

Midsize 5 2534 506.8 18720.2  

Full size 5 2689 537.8 23905.2  

     

     

ANOVA      

Source of Variation SS df MS            F             P-value F crit

Between Groups 94825 3 31608.33 1.321    0.302           3.24

Within Groups 382843.2 16 23927.7    

     

Total 477668.2 19    

Since p value of 0.302 is greater than 0.05 significance level we accept null hypothesis.

p value = 0.302

6 0
3 years ago
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